What is 4 squared + 3 squared

Write an equation for an exponential growth function where the initial population is 80 and the population quadruples during eac

liq [111]

$f(t) = 80(4^t)$

For each time period, each time "t" increases by one, the population will be multiplied by 4.

6 0

3 years ago

Assume the time required to complete a product is normally distributed with a mean 3.2 hours and standard deviation .4 hours. Ho

Alex787 [66]

Answer: 3.712 hours or more

Step-by-step explanation:

Let X be the random variable that denotes the time required to complete a product.

X is normally distributed.

$X\sim N(\mu=3.2\text{ hours},\ \sigma=0.4\text{ hours} )$

Let x be the times it takes to complete a random unit in order to be in the top 10% (right tail) of the time distribution.

Then, $P(\dfrac{X-\mu}{\sigma}>\dfrac{x-\mu}{\sigma})=0.10$

$P(z>\dfrac{x-3.2}{\sigma})=0.10\ \ \ [z=\dfrac{x-\mu}{\sigma}]$

As, $P(z>1.28)=0.10$ [By z-table]

Then,

$\dfrac{x-3.2}{0.4}=1.28\\\\\Rightarrow\ x=0.4\times1.28+3.2\\\\\Rightarrow\ x=3.712$

So, it will take 3.712 hours or more to complete a random unit in order to be in the top 10% (right tail) of the time distribution.

3 0

4 years ago

The area of the curved surface of a cylindrical can is 162 π square centimeters and it’s height is 9 centimeters. What is the di

asambeis [7]

Answer:

Diameter of the can = 18 Cm

Step-by-step explanation:

Given:

Curved surface of cylindrical can = 162 $\pi$

Height of cylindrical can = 9 Cm

Find:

Diameter of the can = ?

Computation:

Curved surface of cylindrical can = 2 $\pi$ rh

$162\pi = 2\pi rh\\\\\frac{162\pi }{2\pi }= r\times 9\\\\81 = r\times 9\\\\\frac{81}{9}=r$

$r=9 Cm$

Diameter of the can = 2×r

Diameter of the can = 2×9 Cm

Diameter of the can = 18 Cm

8 0

3 years ago

You are designing a rectangular sign for your school’s football team. The sign will be 6 yd wide and 9 ft high. How many square

loris [4]

You need to find the area of the rectangle which is 9 times 6. You will need 54 square yards of material

5 0

4 years ago

Task 1:

OleMash [197]

Answer:

maximum height is 4.058 metres

Time in air = 0.033 second

Step-by-step explanation:

Given that the equation height h

h = -212t^2 + 7t + 4

What is the toy's maximum height?

Let us assume that the equation is a perfect parabola

Time t at Maximum height will be

t = -b/2a

Where b = 7 and a = - 212

t = -7/ - 212 ×2

t = 7/ 424 = 0.0165s

Substitute t in the main equation

h = - 212(7/424)^2 + 7(7/424) + 4

h = - 0.05778 + 0.115567 + 4

h = 4.058 metres

Therefore the maximum height is 4.058 metres

How long is the toy in the air?

The object will go up and return to the ground.

At ground level, h = 0

-212t^2 + 7t + 4 = 0

212t^2 - 7t - 4 = 0

You can factorize the above equation and pick the positive time t since time can't be negative

Or

Since we have assumed that it's a perfect parabola,

Total time in air = (-b/2a) × 2

Time in air = 0.0165 × 2 = 0.033 s

3 0

3 years ago