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Novay_Z [31]
3 years ago
9

Projectile motion 1 and 2​

Physics
1 answer:
shtirl [24]3 years ago
8 0

1. Vf =62.57778m/s

h=62.5778

theta final=45°????

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An electron (q=-1.602×10-19C) is placed .03m away from spherical object with a net charge of -7.2 C.
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Answer:

Explanation:

electric field at the location of electron

= 9 x 10⁹ x 7.2 / .03²

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force on electron = electric field x charge on electron

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C )

work done = charge on electron x potential difference at two points

potential at .03 m

= 9 x 10⁹ x 7.2 / .03

= 2.16 x 10¹² V

potential at .001 m

= 9 x 10⁹ x 7.2 / .001

= 64.8 x 10¹² V

potential difference = (64.8 - 2.16 )x 10¹² V

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work done = 62.64 x 10¹² x 1.6 x 10⁻¹⁹

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D )

There will be no change in the magnitude of force on positron except that the direction of force will be reversed . In case of electron , there will be repulsion and in case of positron , there will be attraction .

Work done in case of electron will be positive and work done in case of positron will be negative .

electric field due to charge will be same in both the cases .

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3 years ago
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Rebecca heated 50mL of water from 0 degrees Celsius to 60 degrees Celsius. How much energy did she use to heat the water? Rememb
GuDViN [60]

Answer:

Q = 12540  J

Explanation:

It is given that,

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The correct answer should be C
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serious [3.7K]

Answer:

This is your answer

Explanation:

Actually I took this from go ogle

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3 years ago
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