Projectile motion 1 and 2

Calculate the magnitude of the electric field at one corner of a square 2.42 m on a side if the other three corners are occupied

Karolina [17]

Ans:

12500 N/C

Explanation:

Side of square, a = 2.42 m

q = 4.25 x 10^-6 C

The formula for the electric field is given by

$E = \frac{Kq}{r^2}$

where, K be the constant = 9 x 10^9 Nm^2/c^2 and r be the distance between the two charges

According to the diagram

BD = $\sqrt{2}\times a$

where, a be the side of the square

So, Electric field at B due to charge at A

$E_{A}=\frac{Kq}{a^2}$

$E_{A}=\frac{9\times10^{9}\times 4.25 \times 10^{-6}}{2.42^2}$

EA = 6531.32 N/C

Electric field at B due to charge at C

$E_{C}=\frac{Kq}{a^2}$

$E_{C}=\frac{9\times10^{9}\times 4.25 \times 10^{-6}}{2.42^2}$

Ec = 6531.32 N/C

Electric field at B due to charge at D

$E_{D}=\frac{Kq}{2a^2}$

$E_{D}=\frac{9\times10^{9}\times 4.25 \times 10^{-6}}{2\times 2.42^2}$

ED = 3265.66 N/C

Now resolve the components along X axis and Y axis

Ex = EA + ED Cos 45 = 6531.32 + 3265.66 x 0.707 = 8840.5 N/C

Ey = Ec + ED Sin 45 = 6531.32 + 3265.66 x 0.707 = 8840.5 N/C

The resultant electric field at B is given by

$E=\sqrt{E_{x}^{2}+E_{y}^{2}}$

$E=\sqrt{8840.5^{2}+8840.5^{2}}$

E = 12500 N/C

Explanation:

8 0

4 years ago

Read 2 more answers

A researcher is interested in exploring the effects of exposure to ultraviolet light on people’s emotional state. He divides his

bekas [8.4K]

Answer:

Explanation:

In an experimental research, the control group is the group that serves as the neutral group that is not given any form of treatment and serves as the group in which the experimental groups are firstly compared to. Thus, <u>the control group in the question described is the Third group</u>.

While experimental groups are the groups that receive treatments required to make an inference from the experiment. From this description, <u>it can be deduced that the First and the Second group are the experimental groups.</u>

4 0

3 years ago

pakka acquires a velocity of 72 km per hour in 10 seconds starting from rest find a ) the acceleration b)the average velocity c)

nadezda [96]

Acceleration equals 24 km/s
Average equals 396km/s

8 0

4 years ago

What is the simplest relationship between the angular wavenumber k and just one of the other kinematic variables?

Inessa [10]

Answer : $k=\dfrac{\omega}{k}$

Explanation :

The word kinematics means the study of motion. Kinematic variables gives the description of the motion of the body.

Displacement, Velocity, acceleration and time are associated with the motion of particle.

Wavenumber is defined as the frequency of wave, which is measured in cycles per unit distance.

Wave number is also defines as:

$k=\dfrac{2\pi}{\lambda}$

where, $\lambda$ is wavelength

$k=\dfrac{2\pi}{\lambda}\times \dfrac{T}{T}$

since, $\dfrac{2\pi}{T}=\omega \ and\ \dfrac{1}{V}=\dfrac{T}{\lambda}$

So, $k=\dfrac{\omega}{V}$

Where, $\omega$ is angular frequency and $V$ is velocity of wave.

Hence, the relationship between the angular wavenumber k and and kinamatic variable V is

$k=\dfrac{\omega}{V}$

6 0

4 years ago

Identify the forces acting on the object of interest. From the list below, select the forces that act on the piano.

bekas [8.4K]

The correct answer is the following.

The forces that act on the piano are: 2) gravitational force acting on the piano (piano's weight). 5) force of the floor on the piano (normal force). 7) force of Chadwick on the piano.

As we see in the picture that I have attached is Chadwick pushing the piano in a horizontal plane. So Chadwick is applying a force that produces an acceleration. It is his force on the piano plus the acceleration of the weight of the piano, it's a gravitational force. This is pure physics applied to an object.

5 0

3 years ago

Projectile motion 1 and 2​

Projectile motion 1 and 2