Answer:
False
Explanation:
Carbon and Oxygen can for Carbon Monoxide (CO), Carbon Dioxide (CO2), Carbon Trioxide (CO3), etc.
The mass of
that would be formed will be 18.22 grams
<h3>Stoichiometric calculations</h3>
Let us first look at the balanced equation of the reaction:

The mole ratio of Y to
is 2:3.
Mole of 10.0 grams of Y = 10/88.9 = 0.11 moles
Mole of 10.0 grams
= 10/71 = 0.14 moles
3/2 of 0.11 = 0.165. Thus,
is limiting in availability.
Mole ratio of
and
= 3:2
Equivalent mole of
= 2/3 x 0.14 = 0.093 moles.
Mass of 0.093 moles
=0.093 x 195.26 = 18.22 grams
More on stoichiometric calculations can be found here: brainly.com/question/27287858
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The answer is: the rate of reaction is 850 g/min.
n(P₄O₁₀) = 1.5 mol; amount of product.
M(P₄O₁₀) = 283.9 g/mol; molar mass of phosphorus(V) oxide.
m(P₄O₁₀) = n(P₄O₁₀) · M(P₄O₁₀).
m(P₄O₁₀) = 1.5 mol · 283.9 g/mol.
m(P₄O₁₀) = 425.85 g in 30 seconds.
Make proportion: 425 g : 30 s = m(P₄O₁₀) : 60 s.
m(P₄O₁₀) = 850 g in 60 s.
Answer:

Explanation:
1. First take the cylinder volume formula:

2. Then take the values for the radius and the height of the cylinder and replace them into the formula:

3. Solve the equation:


