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Maksim231197 [3]
3 years ago
14

1. A 50 gram sample of a radioisotope decays to 12.5 grams in 14.4 seconds. What is

Chemistry
2 answers:
stiv31 [10]3 years ago
5 0

Answer:

Half life = 7.2 seconds

Explanation:

from \: decay \: equation \\ 2.303 log( \frac{n.}{nt} )  = kt \\ 2.303 log( \frac{50}{12.5} )  = k \times 14.4 \\ k =  \frac{2.303 log( \frac{50}{12.5} )}{14.4}  \\ k = 0.096288 {s}^{ - 1}  \\ since \: half \: life =  \frac{ ln(2) }{k}  \\ half \: life  =   \frac{ ln(2) }{0.096288}  \\ half \: life = 7.2 \: seconds

sp2606 [1]3 years ago
3 0
14.2 because basically you just divide it by 2 which would be half of it

That will work with all of those problems

So if it’s is a quarter of an isotope you’d divide by 4
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gThe mole fraction of potassium nitrate in an aqueous solution is 0.0194. The solution's density is 1.0627 g/mL. What is the mol
xxMikexx [17]

Answer:

0.595 M

Explanation:

The number of moles of water in 1L = 1000g/18g/mol = 55.6 moles of water.

Mole fraction = number of moles of KNO3/number of moles of KNO3 + number of moles of water

0.0194 = x/x + 55.6

0.0194(x + 55.6) = x

0.0194x + 1.08 = x

x - 0.0194x = 1.08

0.9806x= 1.08

x= 1.08/0.9806

x= 1.1 moles of KNO3

Mole fraction of water= 55.6/1.1 + 55.6 = 0.981

If

xA= mole fraction of solvent

xB= mole fraction of solute

nA= number of moles of solvent

nB = number of moles of solute

MA= molar mass of solvent

MB = molar mass of solute

d= density of solution

Molarity = xBd × 1000/xAMA ×xBMB

Molarity= 0.0194 × 1.0627 × 1000/0.981 × 18 × 0.0194×101

Molarity= 20.6/34.6

Molarity of KNO3= 0.595 M

8 0
3 years ago
On the periodic table, what is used to determine the order of elements? (Use your own words? Help please!!!
Angelina_Jolie [31]

Elements are listed in order of increasing atomic number from the left to the right.

4 0
3 years ago
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Calculate the standard entropy change for the following reaction cu(s) + 1/2 O2(g) —> cuo(s)
Evgen [1.6K]

3433Explanation:

the awser sucks and its not RIGHT

8 0
3 years ago
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Calculate the density of a solid that has a volume of 2cm3 and a mass of 3g
katrin2010 [14]

Answer:

The density is 6

Explanation:

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8 0
3 years ago
A 100-W lightbulb is placed in a cylinder equipped with a moveable piston. The lightbulb is turned on for 0.020 h, and the assem
nasty-shy [4]

Answer: The workdone W = 505J

Explanation:

Applying the pressure-volume relationship

W= - PΔV

Where negative sign indicates the power is being delivered to the surrounding

W = - 1.0atm * ( 5.88 - 0.9)L

= - 1.0atm * (4.98)

W = -4.98 atmL

Converting to Joules

1atmL = 101.325J

-4.98atmL = x joules.

Work done in J = -4.98 * 101.325

W= -505J

Therefore the workdone is -505J

5 0
3 years ago
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