Answer:
B. Titanium alloy rod
Explanation:
Attached is the full solution
An iron pot is mostly magnetic
Answer:
592.92 x 10³ Pa
Explanation:
Mole of ammonia required = 10 g / 17 =0 .588 moles
We shall have to find pressure of .588 moles of ammonia at 30 degree having volume of 2.5 x 10⁻³ m³. We can calculate it as follows .
From the relation
PV = nRT
P x 2.5 x 10⁻³ = .588 x 8.32 x ( 273 + 30 )
P = 592.92 x 10³ Pa
Answer:
Assume that the air resistance on this glob of putty is negligible. Let .
- The velocity of the glob of putty is approximately right before it hits the ceiling.
- It would take about for the glob of putty to reach the ceiling.
Explanation:
Assume that the air resistance on this glob of putty is negligible. Because of gravity, the glob of putty would accelerate downwards at a constant . Since the acceleration points downwards, its value should be negative.
Consider the equation for an object under constant acceleration, where the time taken is unknown.
,
where
- is the final velocity of the object. In this case, the value of
- is the initial velocity of the object. In this case, . Note that in this case,
- is the acceleration on the object. In this case, .
- is the displacement of the object (during the time when its velocity changed from to .) In this case, . The value of
Rearrange the equation for :
.
.
Calculate the value of :
.
It is assumed that there's no air resistance on the glob of putty. As a result, the acceleration of the putty would be constant. The duration of this motion can be found with the equation:
,
where again,
- is the final velocity of the blob of putty,
- is the initial velocity of the blob of putty, and
- is the acceleration of the blob of putty.
Based on the previous conclusion, . Once again, and . (Keep in mind that the value of the acceleration of the blob is negative.)
.
Note that the inputs , , and here are all in standard units. As a result, the value of and from the formula would also be in standard units.
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