1. CuCl2
Cl: 2(-1)= 2-
Cu: 2+
~ON of Cl: 1-
~ON of Cu: 2-
2.CH4
H: 4(1)= 4+
C: 4-
~ON of H: 1+
~ON of C: 4-
a) figure describe ionization energy , electron affinity & electron negativity
b) figure describe Atomic Radius
c) does represent anything
Electronegativity : An atom attracted the bond pair of electrons in a covalent bond is called electronegativity of an element. H-->Cl
Ionization energy : The amount of energy is required to remove of an electron from an isolated gas atom is called Ionization energy. M + IP-----> M+ + e-
Electron affinity: The amount of enery is released when an electron added to an isolated atom is called electron affinity.
X + e- ------> X- =- EA
Atomic radius ; The distance between the center of neuclies and outer most shell is called atomic radius.
Answer:
The answer to your question is below
Explanation:
To solve this problem use the general formulas for Alkanes, Alkenes, and Alkynes.
Alkanes Cn H(2n + 2)
Alkenes Cn H (2n) "n" is the number of Carbons
Alkynes Cn H (2n - 2)
a) CH₄ C₁ H 2(1) +2 = C₁H₂ + ₂ = CH₄ Alkane
b) C₂H₄ C₂ H₂(₂) Alkene
c) C₃H₆ C(₃) H₂ (₃) Alkene
d) C₂H₂ C₂ H₂(₂) - 2 = C₂H₄ - ₂ = C₂H₂ Alkyne
e) C₁₀H₂₂ C₁₀ H₂(₁₁) Alkene
Answer: X2Y3
Explanation: I had the same question ;) (and got it right)
The answer is C. because the dwarf planet's orbit lies between mars and Jupiter but it orbits the sun. Hope it helped!
