Answer:
The distance close to the peak is 597.4 m.
Explanation:
Given that,
Distance of the first ship from the mountain 
Height of island
Distance of the enemy ship from the mountain 
Initial velocity 
Angle = 74.9°
We need to calculate the horizontal component of initial velocity
Using formula of horizontal component

Put the value into the formula


We need to calculate the vertical component of initial velocity
Using formula of vertical component

Put the value into the formula


We need to calculate the time
Using formula of time



We need to calculate the height of the shell on reaching the mountain
Using equation of motion

Put the value in the equation


We need to calculate the distance close to the peak
Using formula of distance

Put the value into the formula


Hence, The distance close to the peak is 597.4 m.
Answer:
reflection is the act of reflecting or the state of being reflected while echo is
reflection of sound waves from a surface back to the initial listener
Answer:
Through Photosynthesis and Respiration Process.
As per the question the wavelength of spectral line of the neutral hydrogen atom is 21 cm.
Spectral line of hydrogen atom will be observed when an electron will jump from higher excited to the ground state. If E is the energy of the ground state and E' is the energy of the higher excited state,the energy emitted when electron will jump from higher excited to ground state is E'-E.
As per Planck's quantum theory -

Where f is the frequency of emitted radiation and h is the Planck's constant.Actually this energy emitted is also electromagnetic in nature. We know that all the electromagnetic radiation will move with the same velocity which is equal to the velocity of light.
The velocity of light c= 3×10^8 m/s.Hence the velocity of wave corresponding to this spectral line is 3×10^8 m/s.
We know that velocity of a wave is the product of frequency and wavelength of that corresponding wave. Mathematically we can write it as-

[
is the wavelength of the wave ]
It is given that wavelength =21 cm=0.21 m
The frequency is calculated as -




Hence the antenna will be tuned to a frequency of 14.2857×10^8 Hz
Here Hertz[ Hz] is the unit of frequency.
Answer:how long it took you to get there and the distance between your house and her house
Explanation: