Let Kaya's savings be 30x and Edgardo's savings be 35x
If they both started saving at the same time:
f(x)=30x
f(x)=35x
Now, sub in values for x in to the function starting with 0. Subtract y2-y1 and x2-x1 for both functions.
For slope: m=y2-y1/x2-x1
so your result will be m=30/1=30 for f(x) = 30x
and m=35/1=35 for f(x) = 35x
so the slopes are m=30 and m=35 respectively!
Answer:
(3 ± √23 * i) /4
Step-by-step explanation:
To solve this, we can apply the Quadratic Equation.
In an equation of form ax²+bx+c = 0, we can solve for x by applying the Quadratic Equation, or x = (-b ± √(b²-4ac))/(2a)
Matching up values, a is what's multiplied by x², b is what's multiplied by x, and c is the constant, so a = 2, b = -3, and c = 4
Plugging these values into our equation, we get
x = (-b ± √(b²-4ac))/(2a)
x = (-(-3) ± √(3²-4(2)(4)))/(2(2))
= (3 ± √(9-32))/4
= (3 ± √(-23))/4
= (3 ± √23 * i) /4
Answer:
≈3hrs 45mins
Step-by-step explanation:
d=300 miles
s=80mph
Formula: distance/speed=time
Using the formula:
300/80=3.75 hours
0.75 hours=45mins
(To work that out ^) 0.75=x/60
∴ 60*0.75=45mins
Solution: 3hrs 45mins
X represents the number that would be added to the silver cars.
x/40= 4
X=40x4
x=160
Subtract the given 20 from 160 because 160 is the total number
160-20=140
Therefore 140 would be added to 20 silver cars to get the ratio1:4
