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Musya8 [376]
3 years ago
11

A heavy rock is shot upward from the edge of a vertical cliff. It leaves the edge of the cliff with an initial velocity of 12 m/

s directed at 26° from the vertical and experiences no appreciable air resistance as it travels. The distance the rock landed was 40.4 m away from the cliff. How high is the cliff?
Physics
1 answer:
jenyasd209 [6]3 years ago
5 0

Answer:

The height of the building is 88.63 m.

Explanation:

Given;

initial component of vertical velocity, v_i = 12 m/s sin 26° = 5.26 m/s

initial horizontal component of the velocity, u_i = 12 m/s cos 26° =10.786 m/s

horizontal distance traveled by the rock, x = 40.4 m

time of flight is calculated as;

x = u_i t

t = x / u_i

t = 40.4 / 10.786

t = 3.75 s

Determine the final vertical velocity of the ball;

v_f = v_i + gt\\\\v_f = 5.26 + (9.8 *3.75)\\\\v_f = 42.01 \ m/s

Determine the height of the rock;

v_f^2 = v_i^2 + 2gh\\\\h = \frac{v_f^2 - v_i^2}{2g}\\\\ h = \frac{(42.01)^2 - (5.26)^2}{2*9.8}\\\\h = 88.63 \ m

Therefore, the height of the building is 88.63 m.

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A projectile of mass 1.800 kg approaches a stationary target body at 4.800 m/s. The projectile is deflected through an angle of
Artyom0805 [142]

Answer:

P = 5.22 Kg.m/s

Explanation:

given,

mass of the projectile = 1.8 Kg

speed of the target = 4.8 m/s

angle of deflection = 60°

Speed after collision = 2.9 m/s

magnitude of momentum after collision = ?

initial momentum of the body = m x v

                                                  = 1.8 x 4.8 = 8.64 kg.m/s

final momentum after collision

momentum along x-direction

P_x = m v cos θ

P_x = 1.8 x 2.9 x  cos 60°

P_x = 2.61 kg.m/s

momentum along y-direction

P_y = m v sin θ

P_y = 1.8 x 2.9 x  sin 60°

P_y = 4.52 kg.m/s

net momentum of the body

P = \sqrt{P_x^2 + P_y^2}

P = \sqrt{4.52^2 + 2.61^2}

 P = 5.22 Kg.m/s

momentum magnitude after collision is equal to P = 5.22 Kg.m/s

5 0
3 years ago
Describe the general relationship between the weight of adult men and the average number of Calories needed daily to maintain a
Alexeev081 [22]

Answer:

The average number of calories needed daily represents the average quantity of calories eliminated by human body due to metabolism and must be compensated by eating and drinking.

The amount of calories contained in the food we eat every day must represent the amount of calories eliminated by the body in that time to have a steady weight.

Explanation:

The average number of calories needed daily represents the average quantity of calories eliminated by human body due to metabolism and must be compensated by eating and drinking. If total quantity of calories in the food we consume every day is higher that the average number of calories needed daily, then weight increases by fat accumulation.

3 0
3 years ago
What type of clouds are associated with low pressure?
Naddik [55]
Cumulus and cumulonimbus<span />
5 0
3 years ago
James Joule (after whom the unit of energy is named) claimed that the water at the bottom of Niagara Falls should be warmer than
Molodets [167]

Answer:

0.12 K

Explanation:

height, h = 51 m

let the mass of water is m.

Specific heat of water, c = 4190 J/kg K

According to the transformation of energy

Potential energy of water = thermal energy of water

m x g x h = m x c x ΔT

Where, ΔT is the rise in temperature

g x h =  c x ΔT

9.8 x 51 = 4190 x ΔT

ΔT = 0.12 K

Thus, the rise in temperature is 0.12 K.

7 0
3 years ago
Carol drops a stone in a mine shaft 122.5 metres deep.How
Verizon [17]

Answer:

 T = 5.36 s

Explanation:

given,

depth of the mine shaft = 122.5 m

speed of the sound = 340 m/s

time taken  = ?

time taken by the stone to reach at the bottom

using equation of motion

s = u t + \dfrac{1}{2}gt^2

initial speed , u = 0 m/s

t = \sqrt{\dfrac{2s}{g}}

t = \sqrt{\dfrac{2\times 122.5}{9.8}}

       t = 5 s

time taken by the sound to travel

    d =v x t

 t = \dfrac{d}{v}

 t = \dfrac{122.5}{340}

    t = 0.36 s

total time taken for the sound to reach carol after dropping the stone

T = 5 + 0.36

 T = 5.36 s

7 0
3 years ago
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