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wolverine [178]
3 years ago
15

1- What do greenhouse gases do in our atmosphere? a. They absorb radiation given off by the Earth b They block harmful radiation

from reaching the Earth c .They keep all the air within the Earth d .They make the Earth cooler
Chemistry
2 answers:
zavuch27 [327]3 years ago
8 0

Answer: A. They absorb radiation given off by the earth.

Explanation: Green house gases are gases that have the capability of trapping the heat energy from the sun in our environment. These special attribute of these gases is what keeps our environment warm and sustain life as we know it. Example of Green House Gases include: carbon dioxide, water vapour and methane.

ivanzaharov [21]3 years ago
6 0

Answer:

A. THEY ABSORBS RADIATION GIVEN OFF BY THE EARTH.

Explanation:

Greenhouse gases are gases capable of absorbing and emitting infrared  radiations in different wavelength range emitted by the earth. These gases include water vapor, carbon iv oxide, methane, ozone, chlorofluorocarbons, nitric oxide, hydrofluorocarbons. These gases contribute to the greenhouse effects and there actions are dependence on their respective characteristics, abundance in the atmosphere and the indirect effects it causes. Earth surfaces absorbs radiant energy from the sun and these radiations are reflected as light or reflected back to space as hear. Greenhouse gases are involved in absorbing and emitting these incoming energies in order to create a balance between the incoming and outgoing energies. This determines the temperature on the earth surface. The earth can be warm or cold depending on the direction the difference in this balance shifts. Without the greenhouse gases the average temperature of the earth will be lower than the expected temperature.

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a solution with a transmittance of 0.44 is analyzed in a spectrophotometer with 6% stray light. calculate the absorbance reporte
IgorLugansk [536]

The absorbance reported by the defective instrument was 0.3933.

Absorbance A = - log₁₀ T

Tm = transmittance measured by spectrophotometer

Tm = 0.44

Absorbance reported in this equipment = -log₁₀ (0.44) = 0.35654

True absorbance can be calculated by true transmittance, Tm = T+S(α-T)

S = fraction of stray light = 6%= 6/100 = 0.06

α= 1, ideal case

T = true transmittance of the sample

Tm = T+S(α-T)

now, T= Tm-S/ 1-S = 0.44-0.06/ 1-0.06 = 0.404233

therefore, actual reading measured is A = -log₁₀ T = -log₁₀ (0.404233)

i.e; 0.3933

To know more about transmittance click here:

brainly.com/question/17088180

#SPJ4

3 0
1 year ago
Large-scale environmental catastrophes _______.
Ymorist [56]

Answer:

D. All of the Above

Explanation:

i just took the test on edgenuity

3 0
3 years ago
Jean's mother lit a candle and placed it on his birthday cake. As they sang happy birthday, the wick burned, the wax
Greeley [361]

Answer:

The wick burning

Explanation:

7 0
3 years ago
Determine the chemical formula for the molecule shown.
OLEGan [10]

Answer: Formula is C4H8O. In every branch of line formula there are Carbon atom. Carbon makes 4 bonds so In branch left in which two CH3-groups are attached there are also an Hydrogen aton which is not shown.

Explanation: Molecule is organic, it is classified as aldehyde.

Hydrocarbons contains only Carbon and Hydrogen atoms, Organic molecules can contain also other atoms.

Reactions of aldehydes are reduction to alcoholes or oxidation to carboxylic acids. It can not for a polymer.

5 0
2 years ago
Since helium is lighter than air, it is difficult to measure the mass of a sample, so to find out the mass of helium in a birthd
d1i1m1o1n [39]

Answer:

0.7457 g is the mass of the helium gas.

Explanation:

Given:  

Pressure = 3.04 atm

Temperature = 25.0 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (25.0 + 273.15) K = 298.15 K  

Volume = 1.50 L

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

3.04 atm × 1.50 L = n × 0.0821 L.atm/K.mol × 298.15 K  

<u>⇒n = 0.1863 moles</u>

Molar mass of helium = 4.0026 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

0.1863\ mole= \frac{Mass}{4.0026\ g/mol}

Mass_{He}= 0.7457\ g

<u>0.7457 g is the mass of the helium gas. </u>

6 0
3 years ago
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