Answer: This can be quickly solved with "traintracks"
Explanation:
You start w/ grams of water and want to find moles of oxygen gas produced.
So you want to Convert:
Grams of water -> moles of water -> moles of oxygen gas.
The two things you need to know to set up the tracks are:
1)Molar mass of water- H2O
Hydrogen - 1.008(x2)
Oxygen - 16.00
Water - 18.016
This is an example of Oxidation
Answer:
Analysis of a sample of a compound composed of carbon, hydrogen, and oxygen shows that the sample contains 18.80 g of C, 2.367 g of H, and 25.04 g of O.
The properties of the compound suggest that the molar mass should be 59.04 g/mol.
How many carbon atoms are there in one molecule of the compound?
Explanation:
Empirical formula mass is
Empirical formula mass =molecular formula mass
Hence,
empirical formula is same as molecular formula.
That is --- 
.
So, the molecule has two carbon atoms in one molecule of the compound.
First let's convert the minutes to hours (multiply minutes by 60 to get hours):
30 × 60 = 1,800 drops/hour
Now that you know how much drops there are per hour, you can multiply this answer by 3 to work out how many drops there are in 3 hours:
1,800 × 3 = 5,400 drops
We know that 5 drops is equal to 1 ml, so we can divide 5,400 by 5 to work out the amount of ml:
5,400 ÷ 5 = 1,080 ml
Therefore, your final answer is 1,080 millilitres (ml)
