All categories

2 years ago

Arrange the following element, lithium, potassium, carbon and fluorine in increasing ionization energy

Chemistry

2 answers:

Monica [59]2 years ago

6 0

Answer:

Potassium, Lithium, Carbon, Fluorine

Explanation:

potassium has the least and Fluorine has the most

Juli2301 [7.4K]2 years ago

4 0

Answer:

flourine(1681),carbon(1086),lithium(520) and potassium(419)

as we can see that the ionization energy of flourine is the highest than carbon than lithium and than potassium

Explanation:

i hope it will help you

You might be interested in

NEEEEEEEEEEEEEEEEED HELP

lakkis [162]

<h3> <u>Answer</u></h3>

4. loses 2 electrons

<h3><u>EXPLANATION</u></h3>

Mg²+ has 10 electrons while Mg has 12 electrons.

7 0

2 years ago

What is a neutron?

Pavlova-9 [17]

B)
<span>
a subatomic particle with no electric charge, found in the nucleus of an atom </span>

5 0

2 years ago

Read 2 more answers

Some kinds of matter are attracted to a magnet. Is this a physical or chemical property of matter?

Anvisha [2.4K]

Answer:

Physical Property

Explanation:

Magnetism is temporary untill you seperate the objects. There is no chemical change involved before, after, or during.

5 0

2 years ago

For doping silicon with boron, silicon specimen was kept in gaseous atmosphere containing B2O3 that maintained the B concentrati

Kay [80]

Solution :

From Fick's law:

$\frac{D_{AB}}{\Delta z } \times (C_{A1}-C_{A2})=N_a$

Mass balance: Exits = Accumulation

$-N_A A = \frac{dm}{dt}$

$-N_A A = \frac{dVp}{dt}$

$-N_A A = \frac{dV}{dt}p$

$-N_A A = \frac{dhA}{dt}$

$-N_A A = \frac{dh}{dt} \times Ap$

From the last step, area cancels out and thus leaves :

$-N_A = \frac{dh}{dt} \times p$

So now we can substitute the $N_A$ by the Fick's law

$\frac{D_{AB}}{\Delta z } \times (C_{A1}-C_{A2})=\frac{dh}{dt} p$

Substituting the values we get

$=\frac{-4 \times 10^{-13}}{0.0001} \times (3 \times 10^{26} - C_{A2}) = \frac{dh}{dt} \times 2.46$

$=-4 \times 10^{-9} \times( 3 \times 10^{26} - C_{A2}) = 0.0001 \times 2.46$

$= -7800 \times 4 \times 10^{-9} \times (3 \times 10^{26}-C_{A2})=0.000246$ $=-(3 \times 10^{26}-C_{A2}) = 7.8846 \times 100 \times \frac{1}{69.62} \times 6.022 \times 10^{23}$

$C_{A2} = 6.85 \times 10^{28} \ \text{ boron atoms} /m^3$

3 0

3 years ago

a given sample of a gas has a volume of 3.0 L at a pressure of 4.0 atm. If the temperature remains constant and the pressure is

pentagon [3]

Answer:-

2.0 L

Explanation:-

Initial Volume = V 1 = 3.0 L

Initial Pressure P 1 = 4.0 atm

New pressure P 2 = 6.0 atm

Using boyle's law

P1 V1 = P2 V2

New Volume V2 = P1 V1 / P2

= 4.0 atm x 3.0 L / 6.0 atm

= 2 .0 L

3 0

2 years ago