Question

Batman (mass = 88.8 kg) jumps straight down from a bridge into a boat (mass = 530 kg) in which a criminal is fleeing. The velocity of the boat is initially +14.5 m/s. What is the velocity of the boat after Batman lands in it?

Answer 1

Answer:

The velocity of the boat after Batman lands in it is 2.08 m/s.

Explanation:

Given that,

Mass of batman $m_{1}= 88.8\ kg$

Mass of boat $m_{2}=530\ kg$

Initial velocity = 14.5 m/s

We need to calculate the velocity of boat

Using conservation of momentum

$m_{1}u=(m_{1}+m_{2})v$...(I)

Where, $m_{1}$=mass of batman

$m_{2}$ =mass of boat

u=initial velocity

v = velocity of boat

Put the value in the equation

$88.8\times14.5=530+88.8\times v$

$v=\dfrac{88.8\times14.5}{530+88.8}$

$v=2.08\ m/s$

Hence, The velocity of the boat after Batman lands in it is 2.08 m/s.