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patriot [66]
3 years ago
6

Can you please send me the answers of these pls I will make you brainlist ​

Physics
1 answer:
olga nikolaevna [1]3 years ago
3 0

Answer:

a)= technology is any appliances which makes our work very fast without much manual effort.It is used to make our life simple and easy.

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The human eye can readily detect wavelengths from about 400 nm to 700 nm. If white light illuminates a diffraction grating havin
nadya68 [22]

Answer:

The range of angles is from 17.50° to 31.76°

Explanation:

The diffraction grid equation is as follows:

dsen\theta=m\lambda

Clearing for \theta

sen\theta=\frac{m\lambda}{d}

\theta=sen^{-1}(\frac{m\lambda}{d})

where \theta is the angle, m is the order, in this case m=1, \lambda is the wavelength, and d is defined as follows:

d=\frac{1}{resolution}

and since the resolution is 750 lines/mm wich is the same as 750lines/1x10^{-3}m

d will be:

d=\frac{1}{750lines/1x10^{-3}m}=\frac{1x10^{-3}m}{750lines}=1.33x10^{-6}m

wich is the distance between each line of the diffraction grating.

substituting the values for m and d:

\theta=sen^{-1}(\frac{(1)\lambda}{(1.33x10^{-6}m)})

And we need to find two angle values: one for when the wavelength is 400nm and one for when it is 700 nm. So we will get the angle range

\theta=sen^{-1}(\frac{(400x10^{-9})}{(1.33x10^{-6}m)})=17.50

and

\theta=sen^{-1}(\frac{(700x10^{-9})}{(1.33x10^{-6}m)})=31.76

The range of angles is from 17.50° to 31.76°

3 0
3 years ago
Adjacent antinodes of a standing wave on a string are 15.0 cmapart. A particle at an antinode oscillates in simpleharmonic motio
viva [34]

Answer:

a)   D = 15 cm , b)  λ = 30.0 cm , c) 0.0850 cm, d) v = 400 cm / s , e)    v = 80.43 cm / s , v = -80.43 cm / s, f)   D₂= 7.5 cm

Explanation:

Standing waves form when two waves of the same frequency travel in opposite directions,

A) in the waves the distance of the nodes and antinode are the same since the wavelength is constant

          D = 15 cm

B) the wavelength is the distance for which the wave repeats itself, in the case of a standing wave, the distance between two nodes is lamita of the wavelength.

        D = λ / 2

         λ=  15 2

         λ = 30.0 cm

C) the amplitude of each wave is 0.0850 cm, the amplitude of the standing wave is double A = 0.17 cm

D) Let's use the speed ratio

        v =  λ f

        f = 1 / T

        v =  λ / T

       v = 30.0 /0.0750

       v = 400 cm / s

E) the transverse speeds are the speed of the oscillatory movement

       y = A cos (wt)

 

      w = 2π f = 2π / T

      w = 2π / 0.0750

      w = 83.78 rad / s

     

      y = 0.850 cos (83.78 t)

Speed ​​is

      v = dy / dt

      v = -A w cost wt

      v = - 0.850 83.78 cos (83.78 t)

      v = -80.43 cos (83.78 t)

The maximum speed when the cosine values ±1

       v = 80.43 cm / s

       v = -80.43 cm / s

F) if we draw a drawing, the distance between two nodes is half the wavelength, at the distance between an antinode synod is half this, it occupies a quarter of the wavelength

      D₂ = ¼  λ

      D₂ = 30.0/4

      D₂= 7.5 cm

5 0
3 years ago
A purse at radius 2.30 m and a wallet at radius 3.45 m travel in uniform circular motion on the floor of a merry-go-round as the
ivolga24 [154]

Answer:

The acceleration of the wallet is 3\hat{i}+6\hat{j}

Explanation:

Given that,

Radius of purse r= 2.30 m

Radius of wallet r'= 3.45 m

Acceleration of the purse a=2\hat{i}+4.00\hat{j}

We need to calculate the acceleration of the wallet

Using formula of acceleration

a=r\omega^2

Both the purse and wallet have same angular velocity

\omega=\omega'

\sqrt{\dfrac{a}{r}}=\sqrt{\dfrac{a'}{r'}}

\dfrac{a}{r}=\dfrac{a'}{r'}

\dfrac{a'}{a}=\dfrac{r'}{r}

\dfrac{a'}{a}=\dfrac{3.45}{2.30}

\dfrac{a'}{a}=\dfrac{3}{2}

a'=\dfrac{3}{2}\times(2\hat{i}+4.00\hat{j})

a'=3\hat{i}+6\hat{j}

Hence, The acceleration of the wallet is 3\hat{i}+6\hat{j}

4 0
3 years ago
A care package is dropped from an airplane flying at 1000 m above sea level with a velocity of 200 m/s to an island. If it takes
ikadub [295]

Answer:3000

Explanation:

4 0
3 years ago
Which of the following objects cannot make a shadow? Broken piece of glass from a window/wooden pane of the same window? Explain
Lorico [155]

Answer:

broken pieces of glass from a window can't form a shadow.

Explanation:

the reason is that shadow is formed only when light rays hits an opaque object, which doesn't let light to pass through it, but glass is a transparent object, hence light rays passes through it forming no shadow..

<em>i</em><em> </em><em>hope</em><em> </em><em>it</em><em> </em><em>helped</em><em>.</em><em>.</em><em>.</em><em>.</em>

4 0
3 years ago
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