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Natasha_Volkova [10]
1 year ago
14

Describe a situation in which you can accelerate even though your speed doesn’t change.

Physics
1 answer:
KATRIN_1 [288]1 year ago
6 0

Acceleration is not the same as speeding up. It refers to any modification of motion's direction or speed. Accelerated motion is any movement that is not constant speed in a straight line.

<h3>What is meant by acceleration?</h3>

The rate at which an object's velocity for time changes is referred to as acceleration in mechanics. They are vector quantities and accelerations. The direction of the net force acting on an object determines the direction of its acceleration.

An object's velocity can alter depending on whether it moves faster or slower or in a different direction. A falling apple, the moon orbiting the earth, and a car stopped at a stop sign are a few instances of acceleration.

The rate at which velocity changes is called acceleration. Acceleration typically indicates a change in speed, but not necessarily. An item that follows a circular course while maintaining a constant speed is still moving forward because the direction of its motion is shifting.

To learn more about acceleration refer to:

brainly.com/question/605631

#SPJ4

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3 years ago
A car approaches you at a constant speed, sounding its horn, and you hear a frequency of 76 Hz. After the car goes by, you hear
Talja [164]

Answer:

70.07 Hz

Explanation:

Since the sound is moving away from the observer then

f_o = f_s\frac {(v+vs)}{v} and f_o = f_s\frac {(v-vs)}{v} when moving towards observer

With f_o of 76 then taking speed in air as 343 m/s we have

76 = f_s\times\frac {(343-vs)}{343}

f_s=\frac {343\times 76}{343-v_s}

Similarly, with f_o of 65 we have

65 = f_s\times\frac {(343+vs)}{343}\\f_s=\frac {343\times 65}{343+v_s}

Now

f_s=\frac {343\times 65}{343+v_s}=\frac {343\times 76}{343-v_s}

v_s=27.76 m/s

Substituting the above into  any of the first two equations then we obtain

f_s=70.07 Hz

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