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Korolek [52]
3 years ago
13

Which observation could lead to the conclusion that an object is non-living?

Physics
2 answers:
hjlf3 years ago
7 0
The object doesn't move.
Elina [12.6K]3 years ago
7 0
An observation could lead to conclusion that an object is nonliving is that it <span>can't perform metabolic processes</span>
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HELP ME
Mazyrski [523]

Answer:

I THINK IT'S <em>D.</em><em>.</em><em>.</em><em>.</em>

<em>HOPE </em><em>SO</em>

3 0
3 years ago
What travels with a sound wave matter, energy or both?
il63 [147K]
Energy travels with sound waves.
8 0
3 years ago
Read 2 more answers
An object accelerates 13.0 m/s2 when a force of 4.4 newtons is applied to it. What is the
velikii [3]

Answer:

0.3384 N

Explanation:

Acceleration = 13 m/s^2

Force = 4.4 N

Force = mass * acceleration

mass = force / acceleration

mass = 4.4 / 13

mass = 0.3384 N

6 0
3 years ago
Ml(d^2θ/dt^2) =-mgθ
Nata [24]

The equation of motion of a pendulum is:

\dfrac{\textrm{d}^2\theta}{\textrm{d}t^2} = -\dfrac{g}{\ell}\sin\theta,

where \ell it its length and g is the gravitational acceleration. Notice that the mass is absent from the equation! This is quite hard to solve, but for <em>small</em> angles (\theta \ll 1), we can use:

\sin\theta \simeq \theta.

Additionally, let us define:

\omega^2\equiv\dfrac{g}{\ell}.

We can now write:

\dfrac{\textrm{d}^2\theta}{\textrm{d}t^2} = -\omega^2\theta.

The solution to this differential equation is:

\theta(t) = A\sin(\omega t + \phi),

where A and \phi are constants to be determined using the initial conditions. Notice that they will not have any influence on the period, since it is given simply by:

T = \dfrac{2\pi}{\omega} = 2\pi\sqrt{\dfrac{g}{\ell}}.

This justifies that the period depends only on the pendulum's length.

4 0
3 years ago
Visible light waves are ______ waves<br> A.mechanical <br> B.electromagnetic
motikmotik
B.Electromagnetic
explanation:
4 0
3 years ago
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