What is the molar mass of KCI

How many liters of hydrogen gas are formed from the complete reaction of 1.04 mol of C? Assume that the hydrogen gas is collecte

Alisiya [41]

The volume is 2.23 liters of hydrogen gas.

Explanation:

moles of C = grams / molecular mass of C

= 1.04 g / 12.011 g/mol.

= 0.086

The ratio between C and H2 is 1 : 1

moles H2 = 0.086

V = nRT / p

= 0.086 x 0.08206 x 316 K / 1.0 atm

V = 2.23 L.

8 0

3 years ago

How can chemical weathering contribute to physical weathering?

lora16 [44]

A-leads to the abrasion of rocks and minerals

A-dense vegetation cover

True

Explanation:

Weathering is the physical disintegration and chemical decomposition of rocks to form sediments and soils.

Agent of weathering are wind, water and glacier.

Chemical weathering contributes to physical weathering in that it leads to the abrasion of rocks and minerals.

During chemical weathering, a rock chemically combines with materials in the environment and weakens it.

When physical weathering processes are induced, grains produced independently weakening of bonds in rocks grind against one another and wears each other off.

An area with a dense vegetation cover undergoes rapid chemical weathering:

Plant roots penetrates deep into the rock and increases the surface area of chemical action.
Plants produce chemicals that combines with rocks and causes them to decay.
Since the area is always moist, chemical action becomes more severe.

Buildings and statues made of stone are subjected to the same degree of weathering as rocks exposed naturally.

This is true.

Statues and buildings weather just like rocks we find in nature.

It is the same sunshine and rain that impacts rocks that also impacts buildings and statues.

So they degrade at the same rate except they are protected.

learn more:

Erosion brainly.com/question/2473244

#learnwithBrainly

5 0

3 years ago

The following molecular equation represents the reaction that occurs when aqueous solutions of silver(I) nitrate and barium chlo

mrs_skeptik [129]

Answer:

Hey, I hope this helps. You gave the equation already balanced so there was no need to do so, the next thing we need to do after balancing is to split the strong electrolytes into ions. Once that is completed we cross off any reoccurring ions. That leaves us with our complete net ionic.

I also recommend you check out Wayne Breslyn on Yt. He is so helpful with equations like these.

5 0

2 years ago

When a person in the hospital is given fluids intravenously, the fluid is typically a saline (salt) solution with about the same

Sati [7]

Answer:

Swelling of the red blood cells occurs.

Explanation:

Distilled water makes the blood hypotonic ,. that is a less concentrated solution, to the body tissues including the red blood cells.
Therefore the water will enter the red blood cells and may cause them to lyse or swell.
Additionally , water will enter the tissue spaces and cause sweling.
But in the case of a hypertonic solution , ( a salt or saline solution ) , This swelling does not happen because the concentration of the saline will be equal or more than the blood. 
Thus the water will flow only from the blood to the solution. This will not cause swelling.
But too much of salt is also not recommended.

5 0

3 years ago

The Haber Process synthesizes ammonia at elevated temperatures and pressures. Suppose you combine 1580 L of nitrogen gas and 351

ikadub [295]

Answer : The volume of reactant measured at STP left over is 409.9 L

Explanation :

First we have to calculate the moles of $N_2$ and $H_2$ by using ideal gas equation.

For $N_2$ :

$PV_{N_2}=n_{N_2}RT$

where,

P = Pressure of gas at STP = 1 atm

V = Volume of $N_2$ gas = 1580 L

n = number of moles $N_2$ = ?

R = Gas constant = $0.0821L.atm/mol.K$

T = Temperature of gas at STP = 273 K

Putting values in above equation, we get:

$1atm\times 1580L=n_{N_2}\times (0.0821L.atm/mol.K)\times 273K$

$n_{N_2}=70.49mole$

For $H_2$ :

$PV_{H_2}=n_{H_2}RT$

where,

P = Pressure of gas at STP = 1 atm

V = Volume of $H_2$ gas = 3510 L

n = number of moles $H_2$ = ?

R = Gas constant = $0.0821L.atm/mol.K$

T = Temperature of gas at STP = 273 K

Putting values in above equation, we get:

$1atm\times 3510L=n_{H_2}\times (0.0821L.atm/mol.K)\times 273K$

$n_{H_2}=156.6mole$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$N_2(g)+3H_2(g)\rightarrow 2NH_3(g)$

From the balanced reaction we conclude that

As, 3 mole of $H_2$ react with 1 mole of $N_2$

So, 156.6 moles of $H_2$ react with $\frac{156.6}{3}\times 1=52.2$ moles of $N_2$

From this we conclude that, $N_2$ is an excess reagent because the given moles are greater than the required moles and $H_2$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the excess moles of $N_2$ reactant (unreacted gas).

Excess moles of $N_2$ reactant = 70.49 - 52.2 = 18.29 moles

Now we have to calculate the volume of reactant, measured at STP, is left over.

$PV=nRT$

where,

P = Pressure of gas at STP = 1 atm

V = Volume of gas = ?

n = number of moles of unreacted gas = 18.29 moles

R = Gas constant = $0.0821L.atm/mol.K$

T = Temperature of gas at STP = 273 K

Putting values in above equation, we get:

$1atm\times V=18.29mole\times (0.0821L.atm/mol.K)\times 273K$

$V=409.9L$

Therefore, the volume of reactant measured at STP left over is 409.9 L

8 0

3 years ago