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ladessa [460]
3 years ago
13

How many grams of iron(III) oxide (Fe(OH)3) may theoretically be produced from 85.0 g FeCl3?

Chemistry
1 answer:
Crank3 years ago
8 0

Answer:

56.0 g

Explanation:

Calculation of the moles of FeCl_3 as:-

Mass = 85.0 g

Molar mass of FeCl_3 = 162.2 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{85.0\ g}{162.2\ g/mol}

Moles= 0.52404\ mol

According to the reaction:-

FeCl_3+3 NaOH\rightarrow Fe(OH)_3+3 NaCl

1 mole of FeCl_3 on reaction forms 1 mole of Fe(OH)_3

Also,

0.52404 mole of FeCl_3 on reaction forms 0.52404 mole of Fe(OH)_3

Moles of Fe(OH)_3  = 0.52404 moles

Molar mass of Fe(OH)_3  = 106.867 g/mol

Mass = Moles*Molar mass = 0.52404\times 106.867\ g = 56.0 g

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<u>Answer:</u>

<u>For A:</u> The wavelength of the light is 1.052\times 10^4nm

<u>For B:</u> The number of photons per joule is 2.063\times 10^{18}

<u>For C:</u> The binding energy of a metal is 1.197 eV.

<u>Explanation:</u>

The equation used to calculate the energy of a photon follows:

E=\frac{hc}{\lambda}            ......(1)

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E = energy of a photon

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Given values:

E = 1.89\times 10^{-20}J

Putting values in equation 1, we get:

\lambda=\frac{(6.626\times 10^{-34}J.s)\times (3\times 10^8m/s)}{1.89\times 10^{-20}J}\\\\\lambda=1.052\times 10^{-5}m

Converting the wavelength into nanometers, the conversion factor used is:

1m=10^9nm

So, \lambda=1.052\times 10^{-5}m\times \frac{10^9nm}{1m}=1.052\times 10^4nm

Hence, the wavelength of the light is 1.052\times 10^4nm

  • <u>For B:</u>

Given values:

\lambda=410nm=410\times 10^{-9}m

Putting values in equation 1, we get:

E=\frac{(6.626\times 10^{-34}J.s)\times (3\times 10^8m/s)}{410\times 10^{-9}m}\\\\E=4.848\times 10^{-19}J

To calculate the number of photons, we use the equation:

\text{Number of photons}=\frac{\text{Total energy}}{\text{Energy of a photon}}

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\text{Number of photons}=\frac{1J}{4.848\times 10^{-19}J}\\\\\text{Number of photons}=2.063\times 10^{18}

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  • <u>For C:</u>

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