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Bas_tet [7]
3 years ago
13

What one is it for only number 2?

Physics
1 answer:
olga_2 [115]3 years ago
5 0
A is 30kg b is car on top of hill c plane in air d full plane
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A race car starting from rest accelerates uniformly at a rare of 4.90 meters per second^2. What is the cars speed after it has t
Vesnalui [34]

From the law of Galileo Galilei  :v²=v₀²+2ad we take the speed

v²=0+2*4.90*200=1960=>v=√1960=44.27 m/s




4 0
3 years ago
If a runner goes 500 meters with an average speed of 7.0 m/s. How long were they running?
ivann1987 [24]

Answer: s=d/t= 500/7.0=71.42 m/s

Explanation:

5 0
3 years ago
The velocity of sound on a particular day outside is 331 meters/second. What is the frequency of a tone if it has a wavelength o
Leya [2.2K]
Answer:
frequency = 5.52 * 10² Hz

Explanation:
the equation that relates velocity, frequency and wavelength is:
velocity = frequency * wavelength

We are given that:
velocity = 331 m/sec
wavelength = 0.6 m

Substitute with the givens in the equation to get the frequency as follows:
velocity = frequency * wavelength
331 = frequency * 0.6
frequency = 331 / 0.6
frequency = 5.52 * 10² Hz

Hope this helps :)
4 0
3 years ago
Jack has two boxes. One is 148g and one is 78g. If jack pushes both boxes with the same amount of force, which will accelerate f
Step2247 [10]
The 78g box, since it has less weight, would accelerate faster. If you had a frictionless surface, and you conducted this experiment, both boxes, without any outside forces, would accelerate at the same rate forever. However, in this problem we must assume the surface is not frictionless. Friction is determined by weight; the more weight, the more friction. Since the 78g box has less weight, it has less friction, making it easier to push with less force.
8 0
4 years ago
Influenced by the gravitational pull of a distant star, the velocity of an asteroid changes from from +19.3 km/s to −18.8 km/s o
muminat

As per above given data

initial velocity = 19.3 km/s

final velocity = - 18.8 km/s

now in order to find the change in velocity

\Delta v = v_f - v_i

\Delta v = -18.8 - 19.3

\Delta v = -38.1 km/s

\Delta v = -3.81 * 10^4 m/s

Part b)

Now we need to find acceleration

acceleration is given by formula

a = \frac{\Delta v}{\Delta t}

given that

\Delta v =- 3.81 * 10^4 m/s

\Delta t = 2.07 years = 6.53 * 10^7 s

now the acceleration is given as

a = \frac{-3.81 * 10^4}{6.53 * 10^7}

a = - 5.84 * 10^{-4}m/s^2

so above is the acceleration

4 0
3 years ago
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