Answer:
Explanation:
mass of pulley, m3 = 1.5 kg 
Radius of pulley, R = 0.09 m 
mass of monkey, m2 = 4.5 kg 
mass of banana bunch, m1 = 3 kg 
Let a is teh acceleration ans T1 and T2 be the tension in the rope. 
The moment of inertia of the pulley 
I = 0.5 x m3 x R² = 0.5 x 1.5 x 0.09 x 0.09 = 0.006075 kgm²
According to Newton's second law 
T1 - m1 g = m1 x a .... (1) 
m2 g - T2 = m2 x a ..... (2) 
(T2 - T1 ) x R = I x α    
where, α is the angular acceleration
α = a / R 
(T2 - T1)R = 0.5 x m3 x R² x a / R 
T2 - T1 = 0.5 x m3 x a ..... (3)   
 from (1), (2) and (3) 


a = 1.78 m/s²
from equation (1) 
T1 = m1 ( g + a) = 3 ( 9.8 + 1.78) = 34.77 N 
from equation (2) 
T2 = m2 (g - a) = 4.5 (9.8 - 1.78) = 36.13 N