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aivan3 [116]
3 years ago
15

What is the net ionic equation for 2AgNO3 + 2NaOH = Ag2O + 2NaNO3 + H2O

Chemistry
1 answer:
soldi70 [24.7K]3 years ago
7 0

Answer:

2Ag⁺ (aq) + 2OH⁻ (aq) → Ag₂O (s) + H₂O (l)

Explanation:

Step 1: RxN

2AgNO₃ + 2NaOH → Ag₂O + 2NaNO₃ + H₂O

Step 2: Define states of matter

2AgNO₃ (aq) + 2NaOH (aq) → Ag₂O (s) + 2NaNO₃ (aq) + H₂O (l)

Step 3: Total Ionic Equation

2Ag⁺ (aq) + 2NO₃⁻ (aq) + 2Na⁺ (aq) + 2OH⁻ (aq) → Ag₂O (s) + 2Na⁺ (aq) + 2NO₃⁻ (aq) + H₂O (l)

Step 4: Cancel out spectator ions

2Ag⁺ (aq) + 2OH⁻ (aq) → Ag₂O (s) + H₂O (l)

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<u>Answer: </u>The correct answer is 1.32 mol H_2

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Then, 3.50 moles of lithium will produce = \frac{1}{2}\times 3.5=1.75mol of hydrogen gas.

  • Now, to know the theoretical yield of hydrogen gas, we use the equation:

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Moles of hydrogen gas = 1.75 mol

Molar mass of hydrogen gas = 2 g/mol

Putting values in above equation, we get:

1.75mol=\frac{\text{Mass of hydrogen gas}}{2g/mol}\\\\\text{Given mass of hydrogen gas}=3.5gl

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Putting values in above equation, we get:

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\text{Moles of hydrogen gas produced}=\frac{2.64g}{2g/mol}=1.32mol

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