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Butoxors [25]
3 years ago
7

Consider the neutralization reaction 2HNO3(aq)+Ba(OH)2(aq)⟶2H2O(l)+Ba(NO3)2(aq) 2HNO3(aq)+Ba(OH)2(aq)⟶2H2O(l)+Ba(NO3)2(aq) A 0.1

10 L0.110 L sample of an unknown HNO3HNO3 solution required 51.9 mL51.9 mL of 0.100 M Ba(OH)20.100 M Ba(OH)2 for complete neutralization. What is the concentration of the HNO3HNO3 solution? concentration:
Chemistry
1 answer:
Kipish [7]3 years ago
7 0

<u>Answer:</u> The concentration of HNO_3 solution will be 0.094 M.

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HNO_3

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is Ba(OH)_2

We are given:

Conversion factor: 1L = 1000 mL

n_1=1\\M_1=?M\\V_1=0.110L=110mL\\n_2=2\\M_2=0.100M\\V_2=51.9mL

Putting values in above equation, we get:

1\times M_1\times 110=2\times 0.100\times 51.9\\\\M_1=0.094M

Hence, the concentration of HNO_3 solution will be 0.094 M.

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