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2 years ago

The chemical equation, 2 Cr + 3 Fe(NO3)2 - 3 Fe + 2 Cr(NO3)3, is an

Chemistry

1 answer:

lana66690 [7]2 years ago

6 0

Answer:

Single replacement reaction (aka single displacement reaction)

Explanation:

In a single replacement reaction, one element is substituted for another in a compound to create a new compound and a new element in the products. The general form is:

A + BC --> B + AC

In the case of this question, Cr and Fe "trade places."

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Calculate (a) the number of moles of hydrogen required to react with 0.0969 moles of nitrogen, and (b) the number of moles of am

Bumek [7]

Answer:

The answer to your question is:

Explanation:

Data

moles H=?

moles of N = 0.0969

moles of NH₃=?

N₂ (g) + 3 H₂ (g) ⇒ 2NH₃ (g)

Process

1.- Set a rule of three to calculate the moles of hydrogen

1 mol of nitrogen ------------- 3 moles of hydrogen

0.0969 moles of N ---------- x

x = (0.0969 x 3) / 1

x = 0.2907 moles of hydrogen

2.- Set a rule of three to calculate the moles of ammonia

1 mol of nitrogen -------------- 2 moles of ammonia

0.0969 mol of N -------------- x

x = (0.0969 x 2) / 1

x = 0.1938 moles of ammonia

5 0

3 years ago

Name Formula: Lead (II) Oxide F) Pb2O G) PbO2 H) PbO I) Pb2O2

garik1379 [7]

Answer:

PbO is the Answer

Explanation:

4 0

3 years ago

25 points! Help please

Sedbober [7]

Answer:

I think its b

Explanation:

but I wouldn't depend on this answer

4 0

3 years ago

Read 2 more answers

A student is asked to standardize a solution of barium hydroxide. He weighs out 0.978 g potassium hydrogen phthalate (KHC8H4O4,

Sav [38]

Answer:

(A) 0.129 M

(B) 0.237 M

Explanation:

(A) The reaction between potassium hydrogen phthalate and barium hydroxide is:

2HA + Ba(OH)₂ → BaA₂ + 2H₂O

Where A⁻ is the respective anion of the monoprotic acid (KC₈H₄O₄⁻).

We convert mass of phthalate to moles, using its molar mass:

0.978 g ÷ 156 g/mol = 9.27x10⁻³ mol = 9.27 mmol

Now we convert mmol of HA to mmol of Ba(OH)₂:

9.27 mmol HA * $\frac{1mmolBa(OH)_{2}}{2mmolHA}$ = 6.64 mmol Ba(OH)₂

Finally we calculate the molarity of the Ba(OH)₂ solution:

6.64 mmol / 35.8 mL = 0.129 M

(B) The reaction between Ba(OH)₂ and HCl is:

2HCl + Ba(OH)₂ → BaCl₂ + 2H₂O

So the moles of HCl that reacted are:

17.1 mL * 0.129 M * $\frac{2mmolHCl}{1mmolBa(OH)_2}$ = 4.41 mmol HCl

And the molarity of the HCl solution is:

4.41 mmol / 18.6 mL = 0.237 M

3 0

3 years ago

Chemical bonding for Rb & nitrogen, Need help!!!

LekaFEV [45]

Covalent bonding!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

5 0

3 years ago