Answer:
.14L or 140mL
Explanation:
This is a classic plug-n-chug problem. Your textbook probably goes over this formula as 
. M stands for molarity of the given substance, and V stands for the volume that the substance occupies.
Simply plug in the values that you're given, like so:
After completing the algebra portion and solving for the unknown, you will be left with x = .14L, which is the volume required to neutralize 30mL of 7M NaOH.
MgCl2
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C The number and types of bonds within the molecule.
Explanation:
In a molecule, the number and types of bonds present determines the amount of available energy therein.
When bonds are broken or formed, energy is usually released.
- Elements combine with one another in order to attain stability in this state.
- Through this process, they form bonds by attraction.
- Where atoms exchange their valence electrons by losing or gaining it, electrovalent bonds form.
- In covalent molecules, electrons are usually shared between atoms.
- An attraction result from this type of interaction.
- The bond formed stores energy in the process.
- When bonds are broken, energy is usually released. The energy accrues when the bond was being formed.
- In molecules, we have covalent bond.
Learn more:
Bond brainly.com/question/7213980
Covalent bonds brainly.com/question/5258547
#learnwithBrainly
Answer:
383.90K
Explanation:
P1 = 851mmHg
T1 = 330K
T2 = ?
P2 = 990mmHg
To solve for P2, we have to use pressure law which states that the pressure of a fixed mass of fixed is directly proportional to its temperature provided that volume remains constant
Mathematically,
P = kT, k = P/T
P1 / T1 = P2 / T2 = P3 / T3 =.......=Pn / Tn
P1 / T1 = P2 / T2
T2 = (P2 × T1) / P1
T2 = (990 × 330) / 851
T2 = 383.90K
The final temperature of the gas is 383.90K
Answer:
a) molarity of CCl3F = 1.12 × 10^-11 mol/dm³
Molarity of CCl2F2 = 2.20 × 10^-11 mol/dm³
B) molarity of CCL3F = 7.96 × 10 ^-13 mol/dm³
Molarity of CCl2F2 = 1.55 × 10^-12 mol/dm³
Explanation:
Using the ideal gas equation:
PV = nRT
Further explanations are found in the attachment below.
