Answer:
1/4
Explanation:
P = IV, and V = IR, so P = I²R.
If R is held constant, and I is cut in half, then power becomes:
P = (I/2)²R
P = 1/4 I²R
So the power reduces by a factor of 4.
As the stan moves 0.94 s before with an acceleration 4.12 m/s^2
so the distance moved by it
![d = \frac{1}{2}at^2[tex]d = \frac{1}{2}*4.12*0.94^2](https://tex.z-dn.net/?f=d%20%3D%20%5Cfrac%7B1%7D%7B2%7Dat%5E2%3C%2Fp%3E%3Cp%3E%5Btex%5Dd%20%3D%20%5Cfrac%7B1%7D%7B2%7D%2A4.12%2A0.94%5E2)

speed gained by the car is given as


now the relative speed of them is given as

relative acceleration is given as

now the distance between them is to be covered


by solving above equation we have

so it will overtake after 6.64 s
its C because i just anwserd it & it was right