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djyliett [7]
4 years ago
10

In order for an external force to do work on a system, Question 9 options: a) there must be a component of the force perpendicul

ar to the motion. b) there must be a component of force parallel to the motion of the object. c) the force can be at any angle relative to the motion of the object.
Physics
1 answer:
zepelin [54]4 years ago
6 0

Answer:

b) there must be a component of force parallel to the motion of the object.

Explanation:

We know that work done on a body by an external force is calculated by the formula given below:

W = F.d = Fd Cos θ

where,

W = Work Done by the force on the body

F = Magnitude of force

d = displacement of the body

θ = The angle between the direction of motion of the body and the force applied

It is clear from the formula of the work done, that "F Cosθ" represents the component of the force, that is acting in the direction of motion of the object or parallel to the direction of motion of the object. So, if there is no component of force parallel to motion of object, then this factor will become zero. As a result, the work done will also be zero.

Therefore, the correct option will be:

b) <u>there must be a component of force parallel to the motion of object.</u>

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Which jovian planet should have the most extreme seasonal changes? a. Saturn b. Neptune c. Jupiter d. Uranus
Maksim231197 [3]

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D). Uranus.

Explanation:

Jovian planets are described as the planets which are giant balls of gases and located farthest from the sun which primarily include Jupiter, Saturn, Uranus, and Neptune.

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3 0
3 years ago
Solve for the unknown in each of these circuits
Tamiku [17]

<u> Ohms law: </u> This law relates voltage difference between two points. Mathematically, the law states that V=IR;

                Where

                          V = voltage difference ; in volts

                          I = Current ; in Amperes

                          R = Resistance ; in ohms

<u>1. Answer : </u> given that R = 10 ; V= 12 V ;  I = ?

From ohms law,    I = V/R

                                = 12/10

                                = 1.2 Amp.

<u>2. Answer:</u>  given that R = 10 ; V= ? ;  I = 5

From ohms law,    V = IR

                                 = 10×5 = 50 V

<u>3 . Answer:</u>  given that R = ? ; V= 120 ;  I = 5

From ohms law,    R =  V/I

                                 = 120/5

                                 = 24 Ω

<u>4 . Answer:</u>  given that R = ? ; V= 10 ;  I = 20

From ohms law,    R =  V/I

                                 = 10/20

                                 = 0.5 Ω

<u>5 . Answer:</u>  given that R = 480 ; V= 24 ;  I = ?

From ohms law,  I =  V/R

                              = 24/480

                              = 0.05 A

<u>6. Answer:</u>  given that R = 150 ; V= ? ;  I = 1

From ohms law,  V = IR

                               = 1 × 150

                               = 150 V


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