Ask question

Ask question

All categories

Katyanochek1 [597]

2 years ago

14

When an airplane is sitting on the ramp, which of Newton's Laws does it exhibit?

1 answer:

antiseptic1488 [7]2 years ago

4 0

It shows the first law of Newton.

The first law states that :-

'If an object is at rest it will be at rest or if it is at motion, it will be in the state of motion until an external force is applied'

Since the airplane is at rest, it will be at rest showing the first law

You might be interested in

What are wind and water erosion not likely to affect

zavuch27 [327]

Answer:

Tides, bodies of water

Explanation:

5 0

2 years ago

Read 2 more answers

read the top corner of picture for directions AWNSER ALL CORECTLY I WILL MAR BRAINLIEST FOR FIRST ANSWER

omeli [17]

Answer:

question

research

hypothesis

experiment

analyze data

conclusion

7 0

2 years ago

Which of the following phases of water has a definite volume but not a definite shape?

tatuchka [14]

Answer:

Gas

Explanation:

Cos Milky Said it. Milky Smart.

7 0

2 years ago

Read 2 more answers

A jet aircraft with mass of 658,055 kilograms is flying straight downward. At an instant the plane's engine is producing an down

sdas [7]

Answer:

The acceleration of the plane is 10.93 m/s² at that instant.

Explanation:

Given:

Mass of aircraft, $m=658055\textrm{ kg}$

Downward thrust produced, $F=1484732.5\textrm{ N}$

Upward resistance force by air, $F_{R}=740492.6\textrm{ N}$

Weight of the aircraft acting donward, $W=mg=658055\times 9.8=6448939\textrm{ N}$

According to Newton's second law, net force acting on an object is equal to the product of mass and its acceleration.

Here, the net force is given as the difference of downward forces and upward forces.

$F_{net}= F+W-F_{R}\\ F_{net}=1484732.5+6448939-740492.6=7193178.9\textrm{ N}$

Now,

$F_{net}=ma\\7193178.9=658055a\\a=\frac{7193178.9}{658055}=10.93\textrm{ }m/s^{2}$

Therefore, the acceleration of the plane is 10.93 m/s² at that instant.

3 0

3 years ago

When the displacement in SHM is equal to 1/4 of the amplitude xm, what fraction of the total energy is (a) kinetic energy and (b

Anna71 [15]

Answer:

$\frac{KE}{TE} = \frac{15}{16}$

b)

$\frac{U}{TE} = \frac{1}{16}$

Explanation:

Let the amplitude of SHM is given as A

so the total energy of SHM is given as

$E = \frac{1}{2}kA^2$

now we know that

a)

kinetic energy is given as

$KE = \frac{1}{2}k(A^2 - x^2)$

here

$x = \frac{A}{4}$

so now we have

$KE = \frac{1}{2}k(A^2 - \frac{A^2}{16})$

$KE = \frac{15}{32}kA^2$

now its fraction with respect to total energy is given as

$\frac{KE}{TE} = \frac{15}{16}$

b)

Potential energy is given as

$U = \frac{1}{2}kx^2$

so we have

$U = \frac{1}{32}kA^2$

so fraction of energy is given as

$\frac{U}{TE} = \frac{1}{16}$

7 0

2 years ago