Answer:
a = 1.25m/s^2
Explanation:
Force = mass x acceleration
Given mass M = 48kg and
Force F = 60N
60 = 48 x a
Divide both sides by 48
60/48 = 48 x a/48
1.25 = a
a = 1.25m/s^2
Answer:
Explanation:
Let the velocity of projectile be v and angle of throw be θ.
The projectile takes 5 s to touch the ground during which period it falls vertically by 100 m
considering its vertical displacement
h = - ut +1/2 g t²
100 = - vsinθ x 5 + .5 x 9.8 x 5²
5vsinθ = 222.5
vsinθ = 44.5
It covers 160 horizontally in 5 s
vcosθ x 5 = 160
v cosθ = 32
squaring and adding
v²sin²θ +v² cos²θ = 44.4² + 32²
v² = 1971.36 + 1024
v = 54.73 m /s
Answer:
15.29m/s
Explanation:
Using the law of conservation of momentum
m1u1+m2u2 = (m1+m2)v
m1 is the mass of the clown = 85kg
u1 is the velocity of the clown = 0m/s (fired out from rest)
m2 is the mass of the cannon = 480kg
u2 is the velocity of the cannon = 18m/s
Let v me the recoil speed of the cannon
Substitute into the formula
85(0)+480(18) = (85+480)v
0+8640 = 565v
v = 8640/565
v = 15.29m/s
Hence the recoil speed of the cannon is 15.29m/s
A because the normal force always acts perpendicular and away from the surface an object is in contact with.