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mrs_skeptik [129]
3 years ago
14

An electrical circuit is powered by a 1.5-volt battery and contains a light bulb producing 5 Ohms of resistance. There is also a

nother 5 Ohm resistor in the circuit. How many amps of current are in this circuit? HINT: V = IR
FAST PLEASE!!
Physics
1 answer:
Fed [463]3 years ago
8 0

Answer:

if the resistor is fitted in series with the bulb , then the current flowing will be 0.15 A.....

if the resistor if fitted in parallel with the bulb ,

the current flowing will be 0.6 A

Explanation:

total potential difference = 1.5V

when resistors in series ,

total equivalent resistance is = 5 + 5 = 10 ohm

so current = 1.5 ÷ 10 = 0.15

when resistors in parallel ,

total equivalent resistance is = (5 × 5)÷(5 + 5) =2.5 ohm

so current = 1.5÷2.5 = 0.6 A

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<em>n</em> - <em>w</em> = 0

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3 years ago
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Answer:

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