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3 years ago

Two Question!

Physics

1 answer:

Zina [86]3 years ago

5 0

Answer:

1.Gravity

2.meter per second

Explanation:

Gravity is the driving force behind all agents of erosion

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Your own car has a mass of 2000 kg. If your car produces a force of 5000 N, how fast will it accelerate?

Sidana [21]

Answer:

2.5m/s²

Explanation:

Given parameters:

Mass of car = 2000kg

Force produced by the car = 5000N

Unknown:

Acceleration of the car = ?

Solution:

According to Newton's second law of motion, Force is a product of mass and acceleration.

Force = mass x acceleration

Now, insert the parameters and find the unknown;

5000 = 2000 x acceleration

Acceleration = $\frac{5000}{2000}$ = 2.5m/s²

7 0

2 years ago

A bus travels a distance of 120 km with a speed of 40km per hour and returns with a speed of 30km per hour calculate the average

Vsevolod [243]

Answer:

35 km/hr

Explanation:

Average speed = (total of the speed)/(the sets of speeds given)

Direction does not matter in this instance since speed is only magnitude,

Average speed = (30 + 40)/2

Average speed = 70 ÷ 2

= 35 km/hr

3 0

2 years ago

A rough estimate of the radius of a nucleus is provided by the formula r 5 kA1/3, where k is approximately 1.3 × 10213 cm and A

Sphinxa [80]

Answer:

Density of 127 I = $\rm 1.79\times 10^{14}\ g/cm^3.$

Also, $\rm Density\ of\ ^{127}I=3.63\times 10^{13}\times Density\ of\ the\ solid\ iodine.$

Explanation:

Given, the radius of a nucleus is given as

$\rm r=kA^{1/3}$ .

where,

$\rm k = 1.3\times 10^{-13} cm.$

A is the mass number of the nucleus.

The density of the nucleus is defined as the mass of the nucleus M per unit volume V.

$\rm \rho = \dfrac{M}{V}=\dfrac{M}{\dfrac 43 \pi r^3}=\dfrac{M}{\dfrac 43 \pi (kA^{1/3})^3}=\dfrac{M}{\dfrac 43 \pi k^3A}.$

For the nucleus 127 I,

Mass, M = $\rm 2.1\times 10^{-22}\ g.$

Mass number, A = 127.

Therefore, the density of the 127 I nucleus is given by

$\rm \rho = \dfrac{2.1\times 10^{-22}\ g}{\dfrac 43 \times \pi \times (1.3\times 10^{-13})^3\times 127}=1.79\times 10^{14}\ g/cm^3.$

On comparing with the density of the solid iodine,

$\rm \dfrac{Density\ of\ ^{127}I}{Density\ of\ the\ solid\ iodine}=\dfrac{1.79\times 10^{14}\ g/cm^3}{4.93\ g/cm^3}=3.63\times 10^{13}.\\\\\Rightarrow Density\ of\ ^{127}I=3.63\times 10^{13}\times Density\ of\ the\ solid\ iodine.$

7 0

3 years ago

1. Which word or phrase best describes entropy?

Mama L [17]

The answer to this question is:

D) Disorder

7 0

3 years ago

Read 2 more answers

Describe the motion of an object that has an acceleration of 0 mi./s squared

miskamm [114]

The object does not move.

5 0

2 years ago