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3 years ago

Two Question!

Physics

1 answer:

Zina [86]3 years ago

5 0

Answer:

1.Gravity

2.meter per second

Explanation:

Gravity is the driving force behind all agents of erosion

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What displacement in cm would occur with a 75 N/m spring if you placed a 300 N weight on the spring?

ollegr [7]

Surface tension=75N/m

Weight=300N

$\\ \bull\tt\longmapsto Surface\:Tension=\dfrac{Weight}{Displacement}$

$\\ \bull\tt\longmapsto Displacement=\dfrac{Weight}{Surface\:Tension}$

$\\ \bull\tt\longmapsto Displacement=\dfrac{300}{75}$

$\\ \bull\tt\longmapsto Displacement=4m$

$\\ \bull\tt\longmapsto Displacement=400cm$

6 0

2 years ago

The 9 kg block is then released and accelerates to the right, toward the 5 kg block. The surface is rough and the coefficient of

Ahat [919]

Complete Question

The complete question is shown on the first and second uploaded image

Answer:

The velocity is $=4.51m/s$

Explanation:

The kinetic energy of the 9 kg can be determined by these expression

Kinetic energy of 9 kg block = initial energy stored - energy lost as a result of friction

Now to obtain the initial energy stored

Let U denote the initial energy stored and

$U = \frac{1}{2} kx^2$

Where x is the length the spring is displaced

k is the force constant of the string

$U = \frac{1}{2} * 627 * (0.6)^2$

$= 112.86 J$

Now referring to the formula above

i.e Kinetic energy of 9 kg block = initial energy stored - energy lost as a result of friction

$\frac{1}{2} mv^2 = 112.86 - \mu_kmgx$

$v^2 = \frac{2(112.86 -\mu_kmgx)}{m}$

$v = \sqrt{\frac{2(112,86- \mu_kmgx)}{m}}$

and we are told that coefficient of friction = 0.4 and the mass is 9 kg ,the acceleration due to gravity $= 9.8m/s^2$ this displacement length of spring = 0.6

Therefore $v = \sqrt{\frac{2(112.86- (0.4 *9*9.8*0.6))}{9} }$

$=4.51m/s$

8 0

2 years ago

All celestial objects we tracted to each other by gravity.Asteroids A and B are 5 meters (m) part. Asteroids C and D are also 5

Nadusha1986 [10]

A. Between asteroids C and D because gravitational attraction is greatest with increased mass.

6 0

2 years ago

What two angles of elevation will enable a projectile to reach a target 15 km downrange on the same level as the gun if the pro

forsale [732]

Angle of projection: 28 degrees or 62 degrees

Explanation:

A projectile consists of two independent motions:

A uniform motion along the horizontal direction
A uniformly accelerated motion along the vertical direction

From the equations of motion, it is possible to derive an expression for the range of a projectile, which is:

$d=\frac{u^2 sin(2\theta)}{g}$

where:

u is the initial speed

$\theta$ is the angle of projection

$g=9.8 m/s^2$ is the acceleration due to gravity

For the projectile in this problem, we have:

d = 15 km = 15,000 m is the range

$u=421 m/s$ is the initial speed

Solving the equation for $\theta$ , we find the possible angle:

$sin (2\theta) = \frac{dg}{u^2}=\frac{(15,000)(9.8)}{(421)^2}=0.829$

Which gives two values of the angle:

$2\theta = 56^{\circ} \rightarrow \theta=28^{\circ}\\2\theta=124^{\circ} \rightarrow \theta=62^{\circ}$

Learn more about projectile:

brainly.com/question/8751410

#LearnwithBrainly

4 0

3 years ago

Using your Periodic Table, which of the elements below is most likely to be a solid at room temperature?

Zinaida [17]

The answer is definitely Potassium

6 0

2 years ago