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VashaNatasha [74]
3 years ago
13

At the train station, you notice a large horizontal spring at the end of the track where the train comes in. This is a safety de

vice to stop the train so that it will not plow through the station if the engineer misjudges the stopping distance. While waiting, you wonder what would be the fastest train that the spring could stop at its full compression, 3.0 ft?
Physics
1 answer:
e-lub [12.9K]3 years ago
6 0

Assume a maximum stopping acceleration of g/2 where g is acceleration due to gravity.

Answer:

2.99 m/s

Explanation:

Stopping distance, s = 3 ft = 0.914 m

final velocity, v = 0

a = g/2 = 4.9 m/s²

Use third equation of motion:

v^2-u^2 = 2as

substitute the values to find the speed of train:

0 -u^2 = 2\times -4.9 \times 0.914 \\u^2=8.96 \\u=2.99 m/s

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First, you will investigate purely vertical motion. The kinematics equation for vertical motion (ignoring air resistance) is giv
AlladinOne [14]

Answer: It takes 2.85 seconds.

Explanation: according to the question, the kinematics equation for vertical motion is

y(t) = y_{0} + v_{0} .t - \frac{1}{2} .gt^{2}

y₀ is the initial postion and equals 0 because it is fired at ground level;

v₀ is the initial speed and eqauls 14m/s;

g is gravity and it is 9.8m/s²;

y(t) is the final position and equals 0 because it is when the pumpkin hits the ground;

Rewriting the equation, we have:

0 + 14t - \frac{1}{2}.9.8.t^{2} = 0

14t - 4.9t² = 0

t(14 - 4.9t) = 0

For this equation to be zero,

t = 0 or

14 - 4.9t = 0

- 4.9t = - 14

t = \frac{14}{4.9}

t = 2.86

It takes 2.86 seconds for the pumpkin to hit the ground.

6 0
3 years ago
How does a swimmers form affect the kinetic and potential energy’s?
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When a swimmer is submerged into the water, the Gravitation energy is transformed into Kinetic Energy instead. Consequently, this also means that when the diver/swimmer chooses to get out of the water and becomes free from the water again, Potential Energy is restored. This is because it allows the swimmer to do further tasks.

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6 0
2 years ago
A 500-n parachutist opens his chute and experiences an air resistance force of 800 n. the net force on the parachutist is then
Tasya [4]

Force of 500 N is acting on the parachutist.

Parachutist applies 500 N force in downward direction.

Answer:

300 N upward

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Total force acting on the parachutist is given by,

F_{net} = air resistance force - force of parachutist

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F_{net} = 300 N

Direction of force is in upward direction because the air resistance force is more than force of parachutist.

6 0
2 years ago
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The terminal velocity is not dependent on which one of the following properties? the drag coefficient 1 the force of gravity 2 c
ahrayia [7]
<h2>Answer: the falling time</h2>

Explanation:

When a body or object falls, basically two forces act on it:  

1. The force of air friction, also called<em> </em><u><em>"drag force"</em></u> D:  

D={C}_{d}\frac{\rho V^{2} }{2}A  (1)

Where:  

C_ {d} is the drag coefficient  

\rho is the density  of the fluid (air for example)

V is the velocity  

A is the transversal area of the object

So, this force is proportional to the transversal area of ​​the falling element and to the square of the velocity.  

2. Its <u>weight </u>due to the gravity force W:  

W=m.g

(2)

Where:  

m is the mass of the object

g is the acceleration due gravity  

So, at the moment <u>when the drag force equals the gravity force, the object will have its terminal velocity:</u>

D=W (3)

{C}_{d}\frac{\rho V^{2} }{2}A=m.g  (4)

V=\sqrt{\frac{2m.g}{\rho A{C}_{d}}}  (5) This is the terminal velocity

As we can see, there is no "falling time" in this equation.

Therefore, the terminal velocity is not dependent on the falling time.

6 0
2 years ago
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