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Marina CMI [18]
2 years ago
12

Without friction, what is the mass of an ball accelerating at 1.8 m/sec2 to which an

Physics
2 answers:
dlinn [17]2 years ago
8 0

Answer:

\boxed {\boxed {\sf C. \ 23.33 \ kg}}

Explanation:

According to Newton's Second Law of Motion, force is the product of mass and acceleration.

F=ma

The mass of the ball is unknown. The ball is accelerating at 1.8 meters per second squared. An unbalanced force of 42 Newtons is applied to the ball.

Convert the units of force. 1 Newton is equal to 1 kilogram meter per second squared, so our answer of 42 Newtons is equal to 42 kg*m/s².

  • F= 42 kg*m/s²
  • a= 1.8 m/s²

Substitute the values into the formula.

42 \ kg*m/s^1 = m * 1.8 \ m/s^2

We are solving for the mass, so we must isolate the variable m. It is being multiplied by 1.8 meters per second squared. The inverse operation of multiplication is division. Divide both sides by 1.8 m/s².

\frac {42 \ kg*m/s^2}{1.8 \ m/s^2} = \frac{a*1.8 \ m/s^2}{1.8 \ m/s^2}

\frac {42 \ kg*m/s^2}{1.8 \ m/s^2} =m

The units of meters per second squared cancel.

\frac {42 \ kg}{1.8 } =m

23.3333333 \ kg=m

Round to the hundredth place. The 3 in the thousandth place tells us to leave the 3 in the hundredth place.

23.33 \ kg \approx m

The mass of the ball is approximately <u>23.33 kilograms.</u>

Juli2301 [7.4K]2 years ago
4 0

Answer:

<h2>23.33 kg </h2>

Explanation:

The mass of the object can be found by using the formula

m =  \frac{f}{a}  \\

f is the force

a is the acceleration

From the question we have

m  = \frac{42}{1.8}   = 23.3333... \\

We have the final answer as

<h3>23.33 kg</h3>

Hope this helps you

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A type of Lead (Pb) ion has a + 4 oxidation number. Sulfur (S) has a — 2 oxidation number. What would be the chemical formula fo
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Explanation:

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Imagine standing on a bathroom scale and reading your weight. now lift one foot and read your weight again. does the scale read
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PLZ HELP IM REALLY CONFUSED a boy is playing catch with his friend. He throws the ball straight up. When it leaves his hand, the
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Answer:

K.E = 100 J

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Initial P.E is also zero due to zero height initially.

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3 years ago
A particle moving in simple harmonic motion with a period T = 1.5 s passes through the equilibrium point at time t0 = 0 with a v
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Answer

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