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Marina CMI [18]
2 years ago
12

Without friction, what is the mass of an ball accelerating at 1.8 m/sec2 to which an

Physics
2 answers:
dlinn [17]2 years ago
8 0

Answer:

\boxed {\boxed {\sf C. \ 23.33 \ kg}}

Explanation:

According to Newton's Second Law of Motion, force is the product of mass and acceleration.

F=ma

The mass of the ball is unknown. The ball is accelerating at 1.8 meters per second squared. An unbalanced force of 42 Newtons is applied to the ball.

Convert the units of force. 1 Newton is equal to 1 kilogram meter per second squared, so our answer of 42 Newtons is equal to 42 kg*m/s².

  • F= 42 kg*m/s²
  • a= 1.8 m/s²

Substitute the values into the formula.

42 \ kg*m/s^1 = m * 1.8 \ m/s^2

We are solving for the mass, so we must isolate the variable m. It is being multiplied by 1.8 meters per second squared. The inverse operation of multiplication is division. Divide both sides by 1.8 m/s².

\frac {42 \ kg*m/s^2}{1.8 \ m/s^2} = \frac{a*1.8 \ m/s^2}{1.8 \ m/s^2}

\frac {42 \ kg*m/s^2}{1.8 \ m/s^2} =m

The units of meters per second squared cancel.

\frac {42 \ kg}{1.8 } =m

23.3333333 \ kg=m

Round to the hundredth place. The 3 in the thousandth place tells us to leave the 3 in the hundredth place.

23.33 \ kg \approx m

The mass of the ball is approximately <u>23.33 kilograms.</u>

Juli2301 [7.4K]2 years ago
4 0

Answer:

<h2>23.33 kg </h2>

Explanation:

The mass of the object can be found by using the formula

m =  \frac{f}{a}  \\

f is the force

a is the acceleration

From the question we have

m  = \frac{42}{1.8}   = 23.3333... \\

We have the final answer as

<h3>23.33 kg</h3>

Hope this helps you

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Please help
Allisa [31]

<u>We are given:</u>

Mass of the rocket = 10 kg

Weight of the Rocket = 100 N

Upward thrust applied by the rocket = 400 N

<u>Net upward force on the rocket:</u>

We are given that gravity pulls the rocket with a force of 100 N

Also, the rocket applied a force of 400N against gravity

Net upward force = Upward thrust - Force applied by gravity

Net upward force = 400 - 100

Net upward force = 300 N

<u>Upward Acceleration of the Rocket:</u>

From newton's second law:

F = ma

<em>replacing the variables</em>

300 = 10 * a

a = 30 m/s²

5 0
3 years ago
Complete the following sentence: How much you pay in taxes depends on _________________________.
solong [7]

Answer:

How much you pay in taxes depends on the amount of your taxable income

Explanation:

The total amount expected to be payed as taxes is a factor of the amount of taxable income earned within the given tax period.

The taxable income is found by subtracting the amount of deductions and exemption allowed in the tax year from the gross income. It is also specified as the adjusted gross income

The set marginal  tax rate indicates the percentage of the taxable income that is to be paid as taxes, such that there are three different ranges or tax brackets and taxes are paid according to the bracket to which a taxable income belongs.

3 0
3 years ago
How does Earth's surface and the structures on the surface change as a result of an earthquake? Help me pls and I will give Brai
EastWind [94]
<span>Earthquakes often cause dramatic changes at Earth's surface. In addition to the ground movements, other surface effects include changes in the flow of groundwater, landslides, and mudflows. Earthquakes can do significant damage to buildings, bridges, pipelines, railways, embankments, dams, and other <span>structures</span></span>
6 0
3 years ago
An 800-kHz radio signal is detected at a point 2.7 km distant from a transmitter tower. The electric field amplitude of the sign
dimaraw [331]

Answer:

Option D is correct: 170 µW/m²

Explanation:

Given that,

Frequency f = 800kHz

Distance d = 2.7km = 2700m

Electric field Eo = 0.36V/m

Intensity of radio signal

The intensity of radial signal is given as

I = c•εo•Eo²/2

Where c is speed of light

c = 3×10^8m/s

εo = 8.85 × 10^-12 C²/Nm²

I = 3×10^8 × 8.85×10^-12 × 0.36²/2

I = 1.72 × 10^-4W/m²

I = 172 × 10^-6 W/m²

I = 172 µW/m²

Then, the intensity of the radio wave at that point is approximately 170 µW/m²

7 0
3 years ago
A very flexible helium-filled balloon is released from the ground into the air at 20. ∘C. The initial volume of the balloon is 5
koban [17]

Answer:

V = 38.0 L

Explanation:

As we know that number of moles will remains conserved inside the balloon

so we will have

moles = \frac{PV}{RT}

here we have

\frac{P_1V_1}{RT_1} = \frac{P_2V_2}{RT_2}

now we have

P_1 = 760 mm Hg

P_2 = 76 mm Hg

V_1 = 5.00 L

T_1 = 20^o C = 293 K

T_2 = -50^o C = 223 K

\frac{(760mm Hg)(5L)}{R(293)} = \frac{(76mm Hg)(V)}{R(223)}

V = 38.0 L

5 0
3 years ago
Read 2 more answers
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