<u>Answer:</u> The correct answer is 
<u>Explanation:</u>
We are given:
The substance having highest positive 
potential will always get reduced and will undergo reduction reaction. Here, silver will always undergo reduction reaction will get reduced.
Chromium will undergo oxidation reaction and will get oxidized.
The half reactions for the above cell is:
Oxidation half reaction: 
Reduction half reaction: 
( × 3)
Net equation: 
Oxidation reaction occurs at anode and reduction reaction occurs at cathode.
To calculate the 
of the reaction, we use the equation:
Putting values in above equation, we get:
Hence, the correct answer is
Answer:
the answer is C hope I helped
Answer:
Δ
N = -1
Explanation:
Step 1: Data given
2 SO2(g) + O2(g) ⇌ 2 SO3(g)
For 2 moles of SO2 we need 1 mol of O2 to produce 2 moles of SO3
Step 2: Calculate Δ
Δ
N wNill be the sum of moles of products minus the sum of moles of reactants.
Number of moles of products = number of moles of SO3 = 2
Number of moles of reactants = number of moles of SO2 + number of moles of O2 = 2 + 1 = 3
Δ
N = 2 - 3 = -1
Answer:
0.231 mol/L
Explanation:
The first step is to write the balanced equation for this reaction:
The second step is to find the number of moles in the acid:
number of moles = volume * concentration
= 0.035 L * 0.275 mol/L
= 0.009625 mol
The third step is to use the molar ratio from the balanced chemical equation to find the number of moles of NaOH that can neutralize 0.009625 mol of sulphuric acid.
n(sulphuric acid) : n(sodium hydroxide)
1 : 2
0.009625 mol : x
x = 0.01925 mol
Fourth step is to calculate the concentration of sodium hydroxide:
