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algol [13]
3 years ago
11

Which of the following isotopes has the same number of neutrons in sulfur-32

Chemistry
1 answer:
kotegsom [21]3 years ago
5 0
Phosphorus 31. because the mass of sulfur 32 minus the number of protons 16 = 16 neutrons and the mass of phosphorus 31 minus the number of protons 15 = 16 neutrons
Final answer: phosphorus 31
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COPY out the following sentences and fill in the gaps.
malfutka [58]

Answer:

1. Hydrogen ions; acidic

2. Alkali; hydroxide ions; alkaline

3a. Sulfuric acid --> 2 Hydrogen ions + sulfate ion

H₂SO₄ --> 2H+ + SO₄²-

3b. Sodium hydroxide --> Sodium ion + Hydroxide ion

NaOH --> Na+ + OH-

Explanation:

1. Sulfuric acid releases hydrogen ions in solution. This makes the solution acidic.

Acids produce hydrogen ions when dissolved in aqueous solutions.

2. Sodium hydroxide is an alkali. It releases hydroxide ions in solution. This makes the solution alkaline.

Alkalis are soluble bases that produce hydroxide ions in solution.

3a. Sulfuric acid --> 2 Hydrogen ions + sulfate ions

H₂SO₄ --> 2H+ + SO₄²-

The equation above is for the ionization of sulfuric acid

b. Sodium hydroxide --> Sodium ion + Hydroxide ion

NaOH --> Na+ + OH-

The equation above is for the ionization of sodium hydroxide

4 0
3 years ago
Calculate the frequency of visible light having a wavelength of 486 nm
hjlf
Ν= c/λ

λ= 486 nm * ( 1 m / 1x10^9 nm) = 4.86 x10^-7 m 

v= (3.00 x 10^8 m/s) /  (4.86 x10^-7 m) 
v= 6.1728395x 10^14 s^-1
= 6.14 x10^-14 Hz
8 0
3 years ago
Which is the only thermal energy that can be transferred through space?
fgiga [73]

Answer:

radiation

Explanation:

radiation is the transfer of heat energy through space by electromagnetic radiation

8 0
3 years ago
For a particular reaction, Δ=−111.4 kJ and Δ=−25.0 J/K.
vichka [17]

Answer:

\Delta G =-103.95kJ

Explanation:

Hello there!

In this case, since the thermodynamic definition of the Gibbs free energy for a change process is:

\Delta G =\Delta H-T\Delta S

It is possible to plug in the given H, T and S with consistent units, to obtain the correct G as shown below:

\Delta G =-111.4kJ-(298K)(-25.0\frac{J}{K}*\frac{1kJ}{1000J} )\\\\\Delta G =-103.95kJ

Best regards!

6 0
3 years ago
Use the balanced equation to work the following problem:
tankabanditka [31]
The answer is 0.841 g AgCl
4 0
3 years ago
Read 2 more answers
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