Density * Volume = Mass
Now we substitute the values in.
19.3 g/cm^3 + 20 cm^3 = 386 g
Mass = 386 g
Alkanes are hydrocarbons with straight, saturated branch chains. Ring-shaped hydrocarbons are cycloalkanes. Alkenes are branch chains that are straight and have at least one double bond. Alkynes are branch chains that are straight and have at least one triple bond.
<h3>What is Hydrocarbon ?</h3>
A hydrocarbon is an organic molecule in organic chemistry that is made completely of hydrogen and carbon. Examples of group 14 hydrides include hydrocarbons. The majority of hydrocarbons are colorless and hydrophobic, and their scents are either insignificant or best characterized by those of gasoline and lighter fluid.
Other side effects from certain hydrocarbons include coma, seizures, abnormal cardiac rhythms, and liver or kidney damage. Some solvents used in paints, dry cleaning, and household cleaning solutions are examples of items that contain hazardous hydrocarbons.
To know more about Hydrocarbon please click here : brainly.com/question/3551546
#SPJ4
Considering that CCL3F gas behave like an ideal gas then we can use the Ideal Gas Law
<span>PV = nRT, however is an approximation and not the only way to resolve this problem with the given data..So,at the end of the solution I am posting some sources for further understanding and a expanded point of view. </span>
<span>Data: P= 856torr, T = 300K, V= 1.1L, R = 62.36 L Torr / KMol </span>
<span>Solving and substituting in the Gas equation for n = PV / RT = (856)(1.1L) /( 62.36)(300) = 0.05 Mol. This RESULT is of any gas. To tie it up to our gas we need to look for its molecular weight:MW of CCL3F = 137.7 gm/mol. </span>
<span>Then : 0.05x 137.5 = 6.88gm of vapor </span>
<span>If we sustract the vapor weight from the TOTAL weight of liquid we have: 11.5gm - 6.88gm = 4.62 gm of liquid.d</span>
<u>8:4 and 4:8</u> both have CCP structure............................... ᐛ
Answer:
The answer to your question is : letter B. 0.25 atm
Explanation:
To solve this problem we need to use the combined gas law:
<u>P₁V₁</u> = <u>P₂V₂</u>
T₁ T₂
Data
P1 = 0.99 atm V1 = 2 l T1 = 273K
P2 = ? V2 = 4 l T2 = 137K
Now, the clear P2 from the equation and we get
P2 = P1V1T2 / T1V2
Substitution P2 = (2 x 0.99 x 137)/(273 x 4)
P2 = 271.26 / 1092
Result P2 = 0.248 atm ≈ 0.25 atm
