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Vedmedyk [2.9K]

3 years ago

10

Water flows over a section of Niagara Falls at the rate of 1.4 × 106 kg/s and falls 49.8 m. How much power is generated by the f

alling water?

1 answer:

Ad libitum [116K]3 years ago

7 0

Answer:

Power= 6.84×10⁸ W

Explanation:

Given Data

Niagara falls at rate of=1.4×10⁶ kg/s

falls=49.8 m

To find

Power Generated

Solution

Regarding this problem

GPE (gravitational potential energy) declines each second is given from that you will find much the kinetic energy of the falling water is increasing each second.

So power can be found by follow

Power= dE/dt = d/dt (mgh)

Power= gh dm/dt

Power= 1.4×10⁶ kg/s × 9.81 m/s² × 49.8 m

Power= 6.84×10⁸ W

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2 years ago

Read 2 more answers

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steposvetlana [31]

Answer:

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Explanation:

The equation for the photoelectric effect is

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where

$\frac{hc}{\lambda}$ is the energy of the incident photon, with

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In this problem, we have

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First of all we can find the energy of the incident photon

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Converting into electronvolts,

$E=\frac{1.05\cdot 10^{-18} J}{1.6\cdot 10^{-19} J/eV}=6.6 eV$

So now we can re-arrange the equation of the photoelectric effect to find the work function of the metal

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3 years ago

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2 years ago

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Answer: B

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2 years ago

Joe is measuring the time it takes for a ball to roll down a ramp. In this experiment Joe takes the measurement 5 times and gets

PolarNik [594]

Step by step solution :

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$\sigma = \sqrt\dfrac{{\sum (x-\bar{x})^2}}{n}$

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2 years ago