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german
2 years ago
11

Particulate matter in the inhaled air is trapped by the __________.

Physics
1 answer:
VladimirAG [237]2 years ago
4 0

Answer:

Particulate matter in the inhaled air is trapped by the <u><em>epithelial mucus.</em></u>

Explanation:

The complete question is:

<em>"Particulate matter in the inhaled air is trapped by the __________. </em>

<em>a. tracheal carina </em>

<em>b. paranasal sinuses </em>

<em>c. pharyngeal muscles </em>

<em>d. epithelial mucus"</em>

The nostril is covered with a mucous membrane that, at its highest part, is formed by an epithelium that contains cells that produce mucus and hair cells covered with fine hairs, called vibratil cilia. Epithelial cells help protect against the entry of microorganisms. In other words, certain types of epithelial cells have tiny hairs called cilia, which help remove foreign substances.

So, <u><em>particulate matter in the inhaled air is trapped by the epithelial mucus.</em></u>

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IN WHAT CONDITION DO SOUND ECHO
DerKrebs [107]

Answer:

The conditions necessary for hearing the echo. The distance between the sound source and the reflecting surface must not be less than 17 metres where the time period between hearing the original sound and its echo should not be less than 0.1 of a second.

6 0
2 years ago
To practice Problem-Solving Strategy 7.2 Problems Using Mechanical Energy II. The Great Sandini is a 60.0-kg circus performer wh
sp2606 [1]

Answer:

v = 15.45 m/s

Explanation:

As per mechanical energy conservation we can say that here since friction is present in the barrel so we will have

Work done by friction force = Loss in mechanical energy

so we will have

W_f = (U_i + K_i) - (U_f + K_f)

here we know that

W_f = F_f . d

W_f = 40 \times 4

W_f = 160 J

Initial compression in the spring is given as

F = kx

4400 = 1100 x

x = 4 m

now from above equation

W_f = (\frac{1}{2}kx^2 + 0) - (mgh + \frac{1}{2}mv^2)

160 = (\frac{1}{2}1100(4^2) + 0) - (60 \times 9.8\times 2.50 + \frac{1}{2}(60)v^2)

160 = 8800 - 1470 - 30 v^2

v = 15.45 m/s

3 0
3 years ago
The magnitude of a force vector is 89.6 newtons (N). The x component of this vector is directed along the +x axis and has a magn
insens350 [35]

Answer:

(a) θ = 33.86°

(b) Ay = 49.92 N

Explanation:

You have that the magnitude of a vector is A = 89.6 N

The x component of such a vector is Ax = 74.4 N

(a) To find the angle between the vector and the x axis you use the following formula for the calculation of the x component of a vector:

A_x=Acos\theta       (1)

Ax: x component of vector A

A: magnitude of vector A

θ: angle between vector A and the x axis

You solve the equation (1) for θ, by using the inverse of cosine function:

\theta=cos^{-1}(\frac{A_x}{A})=cos{-1}(\frac{74.4N}{89.6N})\\\\\theta=33.86\°

the angle between the A vector and the x axis is 33.86°

(b) The y component of the vector is given by:

A_y=Asin\theta\\\\A_y=(89.6N)sin(33.86\°)=49.92N

the y comonent of the vecor is Ay = 49.92 N

3 0
2 years ago
Power plants can be powered by fossil fuels, such as coal or natural gas, or nuclear power to produce steam to turn turbines to
Naddika [18.5K]
<span>Nuclear energy is cleaner while generating electricity. Nuclear fission provides energy without releasing greenhouse gases such as carbon dioxide. However, nuclear power plants generate significant amounts of radioactive waste.  That is why we should not choose nuclear energy over fossil fuel power plants.</span>
7 0
3 years ago
The apparent weight of a student in alift is 564N . if the mass of the student is 60.3kg, what is the acceleration of the lift ?
Yuki888 [10]

Answer:

-.457 m/s^2

Explanation:

Actual weight =   60 .3 (9.81) = 591.54 N

Accel of lift changes this to    60.3 ( 9.81 - L)     where L - accel of lift

                                           60.3 ( 9.81 - L ) = 564

                                               solve for L = .457 m/s^2  DOWNWARD

                                                        so L = - .457 m/s^2

4 0
2 years ago
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