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german
3 years ago
11

Particulate matter in the inhaled air is trapped by the __________.

Physics
1 answer:
VladimirAG [237]3 years ago
4 0

Answer:

Particulate matter in the inhaled air is trapped by the <u><em>epithelial mucus.</em></u>

Explanation:

The complete question is:

<em>"Particulate matter in the inhaled air is trapped by the __________. </em>

<em>a. tracheal carina </em>

<em>b. paranasal sinuses </em>

<em>c. pharyngeal muscles </em>

<em>d. epithelial mucus"</em>

The nostril is covered with a mucous membrane that, at its highest part, is formed by an epithelium that contains cells that produce mucus and hair cells covered with fine hairs, called vibratil cilia. Epithelial cells help protect against the entry of microorganisms. In other words, certain types of epithelial cells have tiny hairs called cilia, which help remove foreign substances.

So, <u><em>particulate matter in the inhaled air is trapped by the epithelial mucus.</em></u>

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Heat flows into a gas in a piston and work is performed on the gas by its surroundings. The amount of work done is equal to the
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Answer:

The Internal energy of the gas did not change

Explanation:

In this situation the Internal energy of the gas did not change and this is because according the the first law of thermodynamics

Δ U = Q - W  ------ ( 1 )

Δ U  = change in internal energy

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Read 2 more answers
A man standing 1.54 m in front of a shaving mirror produces a real, inverted image 15.2 cm from it. What is the focal length of
zavuch27 [327]

Answer:

The focal length is 16.86 cm and the distance of the man  if he wants to form an upright image of his chin that is twice the chin's actual size is 8.43 cm.

Explanation:

Given that,

Object distance u=1.54 m =154 cm

Image distance v = 15.2 cm

Magnification = 2

We need to calculate the focal length

Using formula of mirror

\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}

Put the value into the formula

\dfrac{1}{f}=\dfrac{1}{15.2}+\dfrac{1}{-154}

\dfrac{1}{f}=\dfrac{347}{5852}

f=16.86\ cm

We need to calculate the focal length

Using formula of magnification

m= \dfrac{-v}{u}

Put the value into the formula

2=\dfrac{v}{u}

v = -2u

Using formula of for focal length

\dfrac{1}{f}=\dfrac{1}{u}+\dfrac{1}{v}

\dfrac{1}{16.86}=\dfrac{1}{u}-\dfrac{1}{2u}

\dfrac{1}{16.86}=\dfrac{1}{2u}

2u=16.86

u=\dfrac{16.86}{2}

u=8.43\ cm

Hence, The focal length is 16.86 cm and the distance of the man  if he wants to form an upright image of his chin that is twice the chin's actual size is 8.43 cm.

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3 years ago
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