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Nutka1998 [239]
3 years ago
5

The amount of radiant power produced by the sun is approximately 3.9 ✕ 1026 W. Assuming the sun to be a perfect blackbody sphere

with a radius of 6.96 ✕ 108 m, find its surface temperature (in kelvins).
Physics
1 answer:
fredd [130]3 years ago
4 0

Answer:

T=5797.8  K

Explanation:

Given that

Power P = 3.9 x 10²⁶ W

Radius ,r= 6.96 x 10⁸ m

We know that ,From Plank's law

P = σ A T⁴

σ = 5.67 x 10 ⁻⁸

A= Area ,T= Temperature ( in Kelvin)

T=\left (\dfrac{P}{\sigma A} \right )^{\dfrac{1}{4}}

Now by putting the values

T=\left (\dfrac{P}{\sigma A}\right )^{\dfrac{1}{4}}

T=\left (\dfrac{3.9\times 10^{26}}{5.67\times 10^{-8}\times 4\times \pi \times (6.96\times 10^8)^2} \right )^{\dfrac{1}{4}}

T=5797.8  K

The temperature of surface will be 5797.8 K

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A car and a truck collide in an intersection and the merged wreck continues along. During the collision. both kinetic energy and
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A-delta fibers : A) are small, myelinated fibers. B) transmit pain signals at a slower rate than C-fibers. C) typically transmit
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A

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3 years ago
A 6 m long, uniform ladder leans against a frictionless wall and makes an angle of 74.3 ◦ with the floor. The ladder has a mass
olganol [36]

Answer: µ=0.205

Explanation:

The horizontal forces acting on the ladder are the friction(f) at the floor and the normal force (Fw) at the wall. For horizontal equilibrium,

f=Fw

The sum of the moments about the base of the ladder Is 0

ΣM = 0 = Fw*L*sin74.3º - (25.8kg*(L/2) + 67.08kg*0.82L)*cos74.3º*9.8m/s²

Note that it doesn't matter WHAT the length of the ladder is -- it cancels.

Solve this for Fw.

0= 0.9637FwL - (67.91L)2.652

Fw=180.1/0.9637

Fw=186.87N

f=186.81N

Since Fw=f

We know Fw, so we know f.

But f = µ*Fn

where Fn is the normal force at the floor --

Fn = (25.8 + 67.08)kg * 9.8m/s² =

910.22N

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186.81/910.22

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4 0
3 years ago
A 1000-kg car is moving at 30 m/s around a horizontal unbanked curve whose diameter is 0.20 km. What is the magnitude of the fri
omeli [17]

Answer:

4500 N

Explanation:

When a body is moving in a circular motion it will feel an acceleration directed towards the center of the circle, this acceleration is:

a = v^2/r

where v is the velocity of the body and r is the radius of the circumference:

Therefore, a body with mass m, will feel a force f:

f = m v^2/r

Therefore we need another force to keep the body(car) from sliding, this will be given by friction, remember that friction force is given a the normal times a constant of friction mu, that is:

fs = μN = μmg

The car will not slide if     f = fs,   i.e.

fs = μmg =  m v^2/r

That is, the magnitude of the friction force must be (at least) equal to the force due to the centripetal acceleration

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