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Ghella [55]
3 years ago
14

Ulysis carries a 10kg knapsock while climbing a mountain. If Ulysis weighs 5.8x10^2 N. After 15 mins, he is 8m above the mountai

n. 
a.)Total work?
b.)Power?

I'll give you 94 points PLEASE ANSWERRR!!! URGENT.
Physics
1 answer:
marishachu [46]3 years ago
6 0

HELLO JHUVI THE PROBLEM IS VERY EASY

FIRST,

F=5.8X10^2N & DISPLACEMENT (D)=8M

NOW, WORK=FORCE (F) X DISPLACEMENT (D)

SO WORK =5.8X10^2X8 = 4640 N/M

SO WE HAVE WORK WHICH IS 4640 N/M

SECOND,

POWER = WORK /TIME

SO, POWER = 4640/15 (T=15 MIN GIVEN IN QUESTION)

SO POWER = 309 WATT

THATS IT SIMPLE

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4 years ago
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Wittaler [7]

Answer:

2917.4 m/s

Explanation:

From the question given above, the following data were:

Gravitational acceleration of the Moon (g) = 0.25 times the gravitational acceleration of the earth

Radius (r) of the Moon = 1737 Km

Escape velocity (v) =?

Next, we shall determine the gravitational acceleration of the Moon. This can be obtained as follow:

Gravitational acceleration of the earth = 9.8 m/s²

Gravitational acceleration of the Moon (g) = 0.25 times the gravitational acceleration of the earth

= 0.25 × 9.8 = 2.45 m/s²

Next, we shall convert 1737 Km to metres (m). This can be obtained as follow:

1 Km = 1000 m

Therefore,

1737 Km = 1737 Km × 1000 m / 1 Km

1737 Km = 1737000 m

Thus, 1737 Km is equivalent to 1737000 m

Finally, we shall determine the escape velocity of the rocket as shown below:

Gravitational acceleration of the Moon (g) = 2.45 m/s²

Radius (r) of the moon = 1737000 m

Escape velocity (v) =?

v = √2gr

v = √(2 × 2.45 × 1737000)

v = √8511300

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