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2 years ago

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Why is Mm02 called manganese (IV) oxide?

1 answer:

Minchanka [31]2 years ago

5 0

Answer:

MnO2 M n O 2 is an ionic substance without any oxo-anions, therefore its name has the -ide ending.

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What form of matter has a definite shape and takes up space?

BARSIC [14]

Answer:

If something is in a solid state of matter, it has a definite shape and volume. The volume of an object is the amount of space it occupies. A block of wood placed on a table retains its shape and volume, therefore, it is an example of a solid. If a liquid is poured on that same table, there are very different results

Explanation:

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2 years ago

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State and explain modern periodic table. ⊕⊕

Svetradugi [14.3K]

Explanation:

the physical and chemical properties of an element are periodic functions of their atomic number.

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2 years ago

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Which of the following is the most likeley example of an favorable mutation

Lana71 [14]

A mutation that gives a rabbit a third ear

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2 years ago

The Earth only has a limited supply of fresh water; eventually, we will have to use ocean water. We will purify ocean water thro

Ad libitum [116K]

I believe it is all of the above

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2 years ago

When methanol, CH 3 OH , is burned in the presence of oxygen gas, O 2 , a large amount of heat energy is released. For this reas

luda_lava [24]

<u>Answer:</u> The mass of methanol that must be burned is 24.34 grams

<u>Explanation:</u>

We are given:

Amount of heat produced = 581 kJ

For the given chemical equation:

$CH_3OH(g)+\frac{3}{2}O_2(g)\rightarrow CO_2(g)+2H_2O(l);\Delta H=-764kJ$

By Stoichiometry of the reaction:

When 764 kJ of heat is produced, the amount of methanol reacted is 1 mole

So, when 581 kJ of heat will be produced, the amount of methanol reacted will be = $\frac{1}{764}\times 581=0.7605mol$

To calculate mass for given number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of methanol = 0.7605 moles

Molar mass of methanol = 32 g/mol

Putting values in above equation, we get:

$0.7605mol=\frac{\text{Mass of methanol}}{32g/mol}\\\\\text{Mass of methanol}=(0.7605mol\times 32g/mol)=24.34g$

Hence, the mass of methanol that must be burned is 24.34 grams

4 0

2 years ago