Answer:
<h2>The answer is 4.0 g/mL</h2>
Explanation:
The density of a substance can be found by using the formula
From the question
mass = 40 g
volume = 10 mL
The density of the object is
We have the final answer as
<h3>4.0 g/mL</h3>
Hope this helps you
In NaMnO₄, Mn has the highest oxidation number.
The question is incomplete, the complete question is;
Which of the following species contains manganese with the highest oxidation number?
A) Mn
B) MnF₂
C) Mn₃(PO₄)₂
D) MnCl₄
E) NaMnO₄
In order to ascertain the specie that contains manganese with the highest oxidation number, we must calculate the oxidation number of manganese in each of the species one after the other.
1) For Mn, the oxidation number of Mn is zero because the atom is uncombined.
2) For MnF₂;
Mn has an oxidation number of +2
3) For Mn₃(PO₄)₂
Mn has an oxidation number of +2
4) For MnCl₄
Mn has an oxidation number of +4
5) For NaMnO₄
Mn has an oxidation number of +7
Hence in NaMnO₄, Mn has the highest oxidation number.
Learn more: brainly.com/question/10079361
Answer:
I will say D. The molecules become arranged into regular cubic arrangement. but i'm not 100% sure
Explanation:
D.The transferring of thermal energy from the sun to the earth!
