Question

An object of mass 0.400.40 kg, hanging from a spring with a spring constant of 8.08.0 N/m, is set into an up-and-down simple harmonic motion. What is the magnitude of the acceleration of the object when it is at its maximum displacement of 0.100.10 m

Answer 1

Answer:

Acceleration will be equal to $2m/sec^2$      

Explanation:

We have given mass of the object m = 0.4 kg

Spring constant k = 8 N/m

Maximum displacement of the spring is given x = 0.1 m

From newton's law force is equal to $F=ma$.....eqn 1

By hook's law spring force is equal to $F=kx$ .....eqn 2

From equation 1 and equation 2

$ma=kx$

$0.4\times a=8\times 0.1$

$a=2m/sec^2$

So acceleration will be equal to $2m/sec^2$