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miv72 [106K]
3 years ago
10

An object of mass 0.400.40 kg, hanging from a spring with a spring constant of 8.08.0 N/m, is set into an up-and-down simple har

monic motion. What is the magnitude of the acceleration of the object when it is at its maximum displacement of 0.100.10 m
Physics
1 answer:
sineoko [7]3 years ago
8 0

Answer:

Acceleration will be equal to 2m/sec^2      

Explanation:

We have given mass of the object m = 0.4 kg

Spring constant k = 8 N/m

Maximum displacement of the spring is given x = 0.1 m

From newton's law force is equal to F=ma.....eqn 1

By hook's law spring force is equal to F=kx .....eqn 2

From equation 1 and equation 2

ma=kx

0.4\times a=8\times 0.1

a=2m/sec^2

So acceleration will be equal to 2m/sec^2

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Which type of reaction does this diagram represent?
Sever21 [200]

Nuclear fusion because atomic nuclei combine to form a heavier nucleus. Option A is correct.

<h3>What is nuclear fusion?</h3>

The process by which two or more tiny nuclei unite to generate a bigger nucleus is known as a nuclear fusion reaction.

The more energy it takes to liberate an electron from a smaller atom. This is referred to as binding energy.

As a result, when two little nuclei fuse together, there is more binding energy than when two big nuclei fuse together.

For example, the fusion of two hydrogen atoms produces more energy than the fusion of one helium atom, and surplus energy is expelled into space upon binding.

Nuclear fusion because atomic nuclei combine to form a heavier nucleus.

Hence, option A is correct.

To learn more about nuclear fusion refer to the link;

brainly.com/question/14019172

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8 0
2 years ago
How can liquid pressure phenomena be used in daily life. Give one example with explanation of working​?
N76 [4]

Answer:

An example in which liquid pressure phenomena can be used in daily life is in Water blasting

Explanation:

Water blasting refers application of pressurized water to remove materials from the surface of objects.

There are different varieties of water blasting, including;

Hydrocleaning; Cleaning enabled by the use of high pressure water

Hydrodemolition; Demolition or removal of concrete using pressurized water

Hydrojetting; The spraying of water under pressure on surfaces in order to remove surface contaminants.

8 0
3 years ago
After two hours, 1/16 of the initial amount of a certain radioactive isotope remains undecayed. The half-life of the isotope is:
AlekseyPX
The half life is 30 minutes.
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7 0
3 years ago
A 6 kg bowling ball is accelerated at a rate of 2.3 m/s² down the lane. How much force was necessary to produce this acceleratio
Maurinko [17]
The answer is D hoped this helped
4 0
3 years ago
A particle travels clockwise on a circular path of diameter​ R, monitored by a sensor on the circle at point​ P; the other endpo
kotykmax [81]

We make a graphic of this problem to define the angle.

The angle we can calculate through triangle relation, that is,

sin\theta = \frac{c}{QP}\\sin\theta = \frac{c}{R}\\\theta=sin^{-1}\frac{c}{R}

With this function we should only calculate the derivate in function of c

\frac{d\theta}{dc} = \frac{1}{\sqrt{1-\frac{c^2}{R^2}}}(\frac{c}{R})'\\\frac{d\theta}{dc} = \frac{1}{\sqrt{R^2-c^2}}

That is the rate of change of \theta.

b) At this point we need only make a substitution of 0 for c in the equation previously found.

\frac{d\theta}{dc}\big|_{c=0} = \frac{1}{\sqrt{R^2-0}}\\\frac{d\theta}{dc}\big|_{c=0} = \frac{1}{R}

Hence we have finally the rate of change when c=0.

6 0
3 years ago
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