An object of mass 0.400.40 kg, hanging from a spring with a spring constant of 8.08.0 N/m, is set into an up-and-down simple har
1 answer:
Answer:
Acceleration will be equal to
Explanation:
We have given mass of the object m = 0.4 kg
Spring constant k = 8 N/m
Maximum displacement of the spring is given x = 0.1 m
From newton's law force is equal to .....eqn 1
By hook's law spring force is equal to .....eqn 2
From equation 1 and equation 2
So acceleration will be equal to
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Answer:
B
Explanation:
It will give the of 6 which is least of all the other forces.
4.0²+4.0² = c²
6 = c
Answer:
The answer is
<h2>40 J</h2>Explanation:
The kinetic energy of an object given it's mass and velocity can be found by using the formula
where
m is the mass
v is the velocity
From the question
m = 5 kg
v = 4 m/s
The kinetic energy is
We have the final answer as
<h3>40 J</h3>Hope this helps you
Answer:
a)32.34 N/m
b)10cm
c)1.6 Hz
Explanation:
Let 'k' represent spring constant
'm' mass of the object= 330g =>0.33kg
a) in order to find spring constant 'k', we apply Newton's second law to the equilibrium position 10cm below the release point.
ΣF=kx-mg=0
k=mg / x
k= (0.33 x 9.8)/ 0.1
k= 32.34 N/m
b) The amplitude, A, is the distance from the equilibrium (or center) point of motion to either its lowest or highest point (end points). The amplitude, therefore, is half of the total distance covered by the oscillating object.
Therefore, amplitude of the oscillation is 10cm
c)frequency of the oscillation can be determined by,
f= 1/2π
f= 1/2π
f= 1.57
f≈ 1.6 Hz
Therefore, the frequency of the oscillation is 1.6 Hz