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Korolek [52]
3 years ago
9

What occurs in order to break the bond in a cl2 molecule? explanation please.

Chemistry
2 answers:
alexandr1967 [171]3 years ago
6 0

A cl2 molecule is a diatomic molecule composed of two atoms of identical halogen - chlorine. In this case, this molecule is composed of covalent bonds in which the identical atom- molecule tells that this is also non-polar. To break the bond, energy has to be absorbed to break the intermolecular force that bound the molecule together. 
ipn [44]3 years ago
3 0

Options for the question;

(1) Energy is absorbed.

(2) Energy is released.

(3) The molecule creates energy.

(4) The molecule destroys energy.

Answer:

(1) Energy is absorbed.

Explanation:

Using the Method of elimination;

Option 1 - Energy is absorbed to break bonds. Bond-breaking is an endothermic process. This means this option is correct.

Option 2 - This option is incorrect because bond breaking is endothermic in nature. Energy is being absorbed and not released.

Option 3 and 4 - These optons are wrong because energy can neither be created nor destroyed but can change from one form to another.

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Qual é a etapa onde ocorre a adição de cloro para eliminação de microorganismos patogênicos? AULA DE CIÊNCIAS 6° ano
-BARSIC- [3]

Answer:

A desinfecção

Explanation:

A desinfecção é o processo no qual o cloro é adicionado para matar microorganismos patogênicos prejudiciais, como bactérias, vírus, etc. Este é um processo químico e biológico. alguns desinfetantes comuns são cloro, dióxido de cloro e ozônio.

6 0
3 years ago
An interpenetrating primitive cubic structure like that of CsCl with anions in the corners has an edge length of 664 pm. If the
san4es73 [151]

Answer:

the ionic radius of the anion r^- = 312.52 \ pm

Explanation:

From the diagram shown below :

The anion Cl^- is located at the corners

The cation Cs^+ is located at the body center

The Body diagonal length =  \sqrt{3 \ a }

∴ 2 \ r^+ \ + 2r^- \ = \sqrt{3 \ a}  \\ \\ r^+ +r^- = \frac{\sqrt{3}}{2} a

Given that :

\frac{r^+}{r^-} =0.84   (i.e the  ratio of the ionic radius of the cation to the ionic radius of

                 the anion )

0.84r^- \ + r^- \ = \frac{\sqrt{3}}{2}a  \\ \\  1.84 r^- = \frac{3}{2}a \\ \\ r^- = \frac{\sqrt{3}}{2*1.84}a

Also ; a =  664 pm

Then :

r^- = \frac{\sqrt{3} }{2*1.84}*664 \ pm\\ \\ r^- = 312.52 \ pm

Therefore,  the ionic radius of the anion r^- = 312.52 \ pm

4 0
3 years ago
Fofrffycfcfyguffucggr
ira [324]

Answer:

In his alien language, he said ¨ Hellooooo human¨

Explanation:

4 0
3 years ago
Where is the earth curst thinkest
Dafna11 [192]
The crust of the Earth is thickest beneath the continents. 
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3 years ago
How many phosphorus atoms are there in 1.75 mol of calcium phosphate,<br> Ca3(PO4)2
elena-s [515]

Answer:

It has 2 phosphorus atoms in 1 mol

so for 1.75 mol =2×1.75

Explanation:

need thanks and make me brainiest if it helps you

6 0
3 years ago
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