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3 years ago

You are in a canyon and yell across. It takes 4 seconds for the

Physics

1 answer:

Naya [18.7K]3 years ago

3 0

Answer:

Width = 680 [m]

Explanation:

To solve this problem we must know the speed of sound in the air, conducting an internet search, we find that this speed has a value of v = 340 [m/s].

We apply the following kinematic equation, which relates space to time, to define speed.

v = x /t

where:

x = distance [m]

t = time [s]

v = velocity [m/s]

Now replacing:

x = 340 * 4

x = 1360 [m]

But the width of the cannon is calculated when the sound wave hits the wall of the canyon, so this width is half the distance.

Width = 1360 / 2 = 680 [m]

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Objects have a tendency to resist changing their motion. This property is called: *

Salsk061 [2.6K]

Answer:

The answer your looking for is option 2 - Inertia

3 0

3 years ago

Which is greater, the force exerted by the Earth on the Sun, or the force exerted by the Sun on the Earth? Why?

LekaFEV [45]

Answer:

There is no great force, the force exerted by the Earth on the Sun, and the force exerted by the Sun on the Earth are equal

Explanation:

By definition...

3 0

2 years ago

Please help I literally don’t understand

Veseljchak [2.6K]

Answer:

A= 2

B=3

C=4

D=5

E=7

F=8

H=12

7 0

3 years ago

A delivery truck leaves a warehouse and travels 3.20 km east. The truck makes a right turn and travels 2.45 km south to arrive a

boyakko [2]

Explanation:

It is given that,

Displacement of the delivery truck, $d_1=3.2\ km$ (due east)

Then the truck moves, $d_2=2.45\ km$ (due south)

Let d is the magnitude of the truck’s displacement from the warehouse. The net displacement is given by :

$d=\sqrt{d_1^2+d_2^2}$

$d=\sqrt{3.2^2+2.45^2}$

d = 4.03 km

Let $\theta$ is the direction of the truck’s displacement from the warehouse from south of east.

$\theta=tan^{-1}(\dfrac{2.45}{3.2})$

$\theta=37.43^{\circ}$

So, the magnitude and direction of the truck’s displacement from the warehouse is 4.03 km, 37.4° south of east.

8 0

3 years ago

how do you find work when only given the angle a sled is pulled, the mass, the coefficent of kinetic friction and distance

Sergio039 [100]

Answer:

W = F * s

Work done equals applied force * distance traveled

Apparent weight = M g (1 - sin θ) since some of applied force will lighten sled

μ = coefficient of kinetic friction

F cos θ = force applied to motion of sled

s = distance traveled

[μ M g (1 - sin θ)] cos θ * s = work done in moving sled

Note that F = μ M g if applied force is in the horizontal direction

8 0

2 years ago