The answer would be machines
Hi there!
If they are in opposite direction:
- Let UP be the POSITIVE direction and DOWN be the NEGATIVE direction.
Thus:
∑F = 114.6 - 70.7 = 43.9 N upward
If they are in the SAME, downward direction:
∑F = -114.6 - 70.7 = -185.3
The magnitude is the absolute value, so:
|-185.3| = 185.3 N downward
<span>The collision produces forces between the car and the bug. These forces depend on the momentums of the objects that collide.
Momentum is the product of mass and velocity. The greater the mass the smaller the acceleration. That is the Newton's second law. Because the mass of the car is greater, it's momentum is also greater and the accelaration is smaller. so, the bigger momentum of the car explains the different damage.</span>
![\qquad\qquad\huge\underline{{\sf Answer}}](https://tex.z-dn.net/?f=%5Cqquad%5Cqquad%5Chuge%5Cunderline%7B%7B%5Csf%20Answer%7D%7D)
As we know, period (t)of a wave and it's frequency (f) are Reciprocal of each other, so if one is know then we can just reverse the order to get the other one.
that is :
![\qquad \sf \dashrightarrow \: frequency = \dfrac{1}{period}](https://tex.z-dn.net/?f=%5Cqquad%20%5Csf%20%20%5Cdashrightarrow%20%5C%3A%20%20frequency%20%3D%20%20%5Cdfrac%7B1%7D%7Bperiod%7D%20)
Now, let's move on to problems ~
# 11. f = 15 hertz, t = ?
![\qquad \sf \dashrightarrow \: t = \dfrac{1}{15} \: \: sec](https://tex.z-dn.net/?f=%5Cqquad%20%5Csf%20%20%5Cdashrightarrow%20%5C%3A%20t%20%3D%20%20%5Cdfrac%7B1%7D%7B15%7D%20%20%5C%3A%20%20%5C%3A%20sec)
![\qquad \sf \dashrightarrow \: t \approx0.067 \: \: sec](https://tex.z-dn.net/?f=%5Cqquad%20%5Csf%20%20%5Cdashrightarrow%20%5C%3A%20t%20%5Capprox0.067%20%5C%3A%20%20%5C%3A%20%20sec)
#12. f = 292 hertz, t = ?
![\qquad \sf \dashrightarrow \: t = \dfrac{1}{292} \: \: sec](https://tex.z-dn.net/?f=%5Cqquad%20%5Csf%20%20%5Cdashrightarrow%20%5C%3A%20t%20%3D%20%20%5Cdfrac%7B1%7D%7B292%7D%20%20%5C%3A%20%20%5C%3A%20sec)
![\qquad \sf \dashrightarrow \: t \approx0.0034 \: \: sec](https://tex.z-dn.net/?f=%5Cqquad%20%5Csf%20%20%5Cdashrightarrow%20%5C%3A%20t%20%5Capprox0.0034%20%5C%3A%20%20%5C%3A%20%20sec)
#13. t = 12 seconds, f = ?
![\qquad \sf \dashrightarrow \: f= \dfrac{1}{12} \: \: hertz](https://tex.z-dn.net/?f=%5Cqquad%20%5Csf%20%20%5Cdashrightarrow%20%5C%3A%20f%3D%20%20%5Cdfrac%7B1%7D%7B12%7D%20%20%5C%3A%20%20%5C%3A%20hertz)
![\qquad \sf \dashrightarrow \: f \approx0.083 \: \: hertz](https://tex.z-dn.net/?f=%5Cqquad%20%5Csf%20%20%5Cdashrightarrow%20%5C%3A%20f%20%5Capprox0.083%20%5C%3A%20%20%5C%3A%20%20hertz)