The force is still 1 pound.
The TORQUE around the pivot is (force) x (distance from the pivot) = 1 foot-pound. (B)
Answer:
0.75 m³/s
Explanation:
Applying,
Q = vA.................... Equation 1
Where Q = flow rate of the water, v = velocity of the water, A = area of the pipe.
From the question,
Given: v = 2.5 m/s, A = 0.3 m²
Substitute these values into equation 1
Q = 2.5(0.3)
Q = 0.75 m³/s
Hence the flow rate of water in the pipe is 0.75 m³/s
The time for the police car to catch up with the speeding motorist is 7.6 seconds.
<h3>What time will the police car catch up with the speeding motorist?</h3>
The police car and the motorist will cover equal distances.
Let the distance covered be d.
Distance covered by the motorist = speed * time
time = t, speed = 30 m/s
d = 30t
Distance covered by the police car = acceleration * (time)
time = t - 2, acceleration = 5.0 m/s²
d = 5(t-2)²
d = 5(t² - 4t + 4)
d = 5t² - 20t + 20
Equating the two equations for distance
5t² - 20t + 20 = 30t
5t² - 50t + 20 = 0
Solving for t using the quadratic formula:
t = 9.6 second or 0.4 seconds
Since t > 2, t = 9.6 seconds
t - 2 = 9.6 - 2
t - 2 = 7.6 seconds
Therefore, the time for the police car to catch up with the speeding motorist is 7.6 seconds.
Learn more about distance and acceleration at: brainly.com/question/14344386
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Answer:
The magnitude of the change in momentum of the stone is 5.51kg*m/s.
Explanation:
the final kinetic energy = 1/2(0.15)v^2
1/2(0.15)v^2 = 70%*1/2(0.15)(20)^2
v^2 = 21/0.075
v^2 = 280
v = 16.73 m.s
if u is the initial speed and v is the final speed, then:
u = 20 m/s and v = - 16.73m/s
change in momentum = m(v-u)
= 0.15(- 16.73-20)
= -5.51 kg*m.s
Therefore, The magnitude of the change in momentum of the stone is 5.51kg*m/s.
