When the velocity of an object Changes it is acted upon by a

Which tuning fork test evaluates conductive and sensorineural hearing loss in both ears at the same time

Flura [38]

The Rinne and Weber tests are frequently used to detect conductive and sensorineural deafness.

Another test to assess conductive and sensorineural hearing impairments is the Weber test. When sound waves cannot flow from the middle ear to the inner ear, conductive hearing loss results.

This may be brought on by issues with the eardrum, middle ear, or ear canal, such as an infection. A helpful, quick, and easy screening test for determining hearing loss is the Weber test.

The test can identify unilateral sensorineural and conductive hearing loss. Conduction hearing is mediated by the middle and outer ear. A tuning fork is used in the Weber test, a hearing screening procedure. It can identify unilateral sensorineural hearing loss and unilateral conductive hearing loss in the middle ear.

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7 0

2 years ago

A 7500 kg truck traveling at 5.0 m/s east collides with a 1500 kg car moving

julia-pushkina [17]

Since the collision is inelastic, both vehicle will move with a common velocity of 2.5 m/s in south east direction after collision.

<h3>Conservation of Linear Momentum</h3>

It states that, the sum of the momentum before collision is equal to the sum of the momentum after collision.

Given that a 7500 kg truck traveling at 5.0 m/s east collides with a 1500 kg car moving at 20 m/s in a direction 30° south of west. After collision, the two vehicles remain tangled together.

The given parameters are;

M1 = 7500 kg

U1 = 5 m/s

M2 = 1500

U2 = 20 sin 30 = 10 m/s

V = ?

The formula to find the speed will be

M1U1 - M2U2 = (M1 + M2)V

7500 × 5 - 1500 × 10 = (7500 + 1500)V

37500 - 15000 = 9000V

22500 = 9000V

V = 22500/9000

V = 2.5 m/s

Therefore, the common speed will be 2.5 m/s and the direction of the car will be toward the south east.

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5 0

1 year ago

the fastest airplane is the lockheed sr 71 blackbird a high altitude spy plane first built in 1964. if an sr-71 is clocked trave

devlian [24]

For the motion of the plane it is given to us that it travel 15.0 km in 15.3 s

So here we can use the formula of average velocity to find it

formula is given as ratio of total displacement and total time

$v = \frac{displacement}{time}$

here it is given that

$displacement = 15.0 km$

time = 15.3 s

we need to convert the time into hour as the speed is required in km/h

so we know that

$1 h = 3600 s$

$t = 15.3 s * \frac{1h}{3600 s}$

$t = 4.25 * 10^{-3} h$

now by the above formula

$v = \frac{15.0}{4.25 * 10^{-3}}$

$v = 3529.4 km/h$

so the velocity of the plane would be 3529.4 km/h

8 0

4 years ago

In the Bohr theory of the hydrogen atom, an electron moves in a circular orbit about a proton, where the radius of the orbit is

Alchen [17]

Answer:

(a) Electric force will be $77.285\times 10^{-9}N$

(B) Velocity $v=2.1522\times 10^6m/sec$

Explanation:

We have given that radius of the circular orbit $r=0.546\times 10^{-10}m$

Charge on electron $e=1.6\times 10^{-19}C$

(A) According to coulomb's law electric force between two charges is given by

$F=\frac{kq}{r^2}$

So electric force $F=\frac{9\times 10^9\times (1.6\times 10^{-19})^2}{(0.546\times 10^{-10})^2}=77.285\times 10^{-9}N$

We know that centripetal force is given by $F=\frac{mv^2}{r}$

So $\frac{9.11\times 10^{-31}\times v^2}{0.546\times 10^{-10}}=77.285\times 10^{-9}$

$v=2.1522\times 10^6m/sec$

8 0

3 years ago

A certain laser outputs pure red light (photon energy 1.8 eV) with power 550 milliwatts (0.55 watts). How many photons per secon

Klio2033 [76]

We want to find how many photons per second a laser emits given that we know the energy of a single photon and the power of the laser, we will get:

1.90712*10^18 photons per second.

So we know that the photon energy is 1.8 eV, and the laser power is:

P = 0.55 watts

Remember that:

1 watt = 1 J/s

And:

1 eV = 1.60218*10^(-19) J

Then we can convert the two values that we have so we have both in joules:

Power = P = 0.55 J/s

Energy = 1.8 eV = 1.8*(1.60218*10^(-19) J) = 2.883924*10^(-19) J

The number of photons emitted per second is just the quotient between the power and the energy of a single photon, we have:

Number = (0.55 J/s)/(2.883924*10^(-19) J) = 1.90712*10^18 photons per second.

If you want to learn more, you can read:

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5 0

3 years ago