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4 years ago

Which combination of these devices monitors waves that have a compressional component?

Physics

2 answers:

maw [93]4 years ago

5 0

Answer:

It's A

Explanation:

I & II Both seismic waves (that cause earthquakes) and sound waves (which sonar uses) can be compressed because they are longitudinal. All other wave types are electromagnetic waves and cannot be compressed.

kompoz [17]4 years ago

4 0

Answer:

The answer is A

Explanation:

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An upward force act on a proton as it moves with a speed of 2.0 x 10^5 meters/seconds through a magnetic field of 8.5 x 10^2

Gekata [30.6K]

Force on a moving charge is given by formula

$\vec F = q(\vec v \times \vec B)$

here we know that this force will be maximum when velocity is perpendicular to magnetic field

$\vec F = qvB$

here we know that

$v = 2.0 \times 10^5 m/s$

$q = 1.6 \times 10^{-19} C$

$B = 8.5 \times 10^2 T$

now we have

$F = (1.6 \times 10^{-19})(2 \times 10^5)(8.5 \times 10^2)$

$F = 2.72 \times 10^{-11} N$

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4 years ago

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3 years ago

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Find the net work done by friction on the body of a snake slithering in a complete circle of radius. The coefficient of friction

Tamiku [17]

Answer:

C. 0 J

Explanation:

When an object moves in a circle, friction provides the centripetal force. Hence, it is acting towards the centre of the circle. The displacement of the object is tangential to the circle at the point of interest. Hence, the angle between the frictional force and the displacement is 90°.

Work done is given by

W = Fd cos θ

where F is the force, d is the displacement and θ is the angle between them.

W = Fd cos 90° = 0 J

Hence, the work done by friction is 0 J.

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3 years ago

What is the focal length of a lens? the distance between the object and the image distance between the object and the center of

maks197457 [2]

Distance between the focal point and the center of the lens

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3 years ago

The average daily demand for component B is 750 units. The average time for waiting during the production process and materials

Greeley [361]

Answer:

4 containers

Explanation:

Given

Average daily demand, d= 750 units

Average time for waiting during production and materials handling, w = 0.15 days

Processing time per container, t = 0.1 days

Container capacity, c = 50 units

Policy variable, α = 5% = 0.05

Number of containers required for component B is calculated as follows;

Total Production/Container Capacity.

Total Production = d(w + t)(1 + α)

Total Production = 750 * (0.15 + 0.1) * (1 + 0.05)

Total Production = 196.875

Number of containers = 196.875/50

Number of containers = 3.9375

Number of containers = 4 --- approximated

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3 years ago

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