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3 years ago

Is carbon a metal that can conduct electricity?

Physics

1 answer:

gayaneshka [121]3 years ago

5 0

Answer:

carbon is a non metal that can conduct electricity

Explanation:

an example would be graphite

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A delivery truck leaves a warehouse and travels 2.60 km north. The truck makes a left turn and travels 1.25 km west before makin

yulyashka [42]

Answer:

4.19 km and 107.35 degrees north of east

Explanation:

So in the end, the truck is (2.6 + 1.4 = 4km) north and 1.25 km west from the warehouse. We can use the Pythagorean formula to calculate the magnitude and direction α of the truck displacement from the warehouse:

$s = \sqrt{s_n^2 + s_w^2} = \sqrt{4^2 + 1.25^2} = \sqrt{16 + 1.5625} = \sqrt{17.5625} = 4.19$ km

$tan\alpha = \frac{s_n}{s_w} = \frac{4}{1.25} = 3.2$

$\alpha = tan^{-1}3.2 = 1.27 rad \approx 72.65 degrees$ north or west or (180 - 72.65) = 107.35 degrees north of east

3 0

3 years ago

Look at the equation. What detail is missing? 3 m/s2= (33 m/s - X)/30 S <br>

Tems11 [23]

Answer:

The starting velocity.

Explanation:

We must understand that this equation comes from the following equation of kinematics.

$v_{f}=v_{o}+a*t$

where:

Vf = final velocity = 33 [m/s]

Vo = starting velocity [m/s]

a = acceleration = 3 [m/s²]

t = time = 30 [s]

So, these values can be assembly in the following way:

$v_{f}=v_{o}+a*t\\a*t=v_{f}-v_{o}\\3=\frac{33-v_{o}}{30}$

6 0

3 years ago

PLEASE HELP!!<br><br> i’ll mark brainliest if you’re correct

Leno4ka [110]

5Newtons or 5N

Ten newtons minus five Newton’s is 5 Newton’s

5 0

2 years ago

Read 2 more answers

How many photons strike the cd surface during the playing of a cd 69 minutes in length?

Reptile [31]

Answer:

Photons strike the CD $n=1.624 x10^{18}$

Explanation:

First of all, it is necessary to calculate the energy produced by a semiconductor laser for 69 minutes:

$69minutes*\frac{60s}{1 minute}=4140s$

$E=0.1x10^{-3}w*4140s=0.414J$

Next, it is possible to calculate the number of photons striking the CD surface during this time:

$E=\frac{n*h*c}{l}$

$l=780x10^{-9}m$ long in CD

$c=3x10^8 m/s$ light velocity

$h=6.626x10^{-34} J*s$

Solve to n'

$n=\frac{E*l}{c*h}=\frac{0.414 J*780x10^{-9}m}{3x10^8m/s*6.626x10^{-34}}$

$n=1.624 x10^{18}$

8 0

3 years ago

If the current direction is reversed in one of the strips, the magnetic field in a point A located outside the space between the

serious [3.7K]

Answer:

Twice the initial value

Explanation:

Let the current be = I

the width of the conducting strips be = a

We know that magnetic field between two plates is given by

$B=\frac{\mu_0 I}{2\pi r}$

If the direction of this magnetic field is same between the two plates, then

$B=\frac{\mu_0 I}{2\pi r} - \frac{\mu_0 I}{2\pi r}$

= 0

And when the currents runs opposite at each plate, then

$B=\frac{\mu_0 I}{2\pi r} + \frac{\mu_0 I}{2\pi r}$

$2 \times B_{initial}$

Hence the magnetic field will be twice the initial value of the magnetic field that runs between the plates.

6 0

3 years ago