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dusya [7]
2 years ago
7

Ginny is snowboarding down a ski slope. Her total mass (including the snowboard) is 68.5 kg. When she reaches the bottom of the

slope, she is moving at 6.55 m/s. The coefficient of friction between the snowboard and the ground is 0.088 . How fast will Ginny be moving 2 seconds after reaching the bottom of the slope?
1) 5.71 m/s
2)5.91 m/s
3)4.82 m/s
4)4.08 m/s
Physics
2 answers:
iragen [17]2 years ago
7 0

Answer:

5.71

Explanation:

is wrong

tigry1 [53]2 years ago
5 0

Answer:

Explanation:

Assuming the run out at the bottom of the slope is horizontal

μ = Ff/N = Ff/mg

Ff = μmg

a = Ff/m = μmg/m = μg

v = u + at

v = u + μgt

v = 6.55 - 0.088(9.81)(2)

v = 4.82 m/s

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Your lab instructor has asked you to measure a spring constant using a dynamic method—letting it oscillate—rather than a sta
yuradex [85]

Answer:

  k = 6,547 N / m

Explanation:

This laboratory experiment is a simple harmonic motion experiment, where the angular velocity of the oscillation is

         w = √ (k / m)

angular velocity and rel period are  related

         w = 2π / T

substitution

         T = 2π √(m / K)

in Experimental measurements give us the following data

  m (g)     A (cm)    t (s)   T (s)

  100        6.5         7.8    0.78

  150        5.5          9.8   0.98

   200      6.0        10.9    1.09

   250       3.5        12.4    1.24

we look for the period that is the time it takes to give a series of oscillations, the results are in the last column

        T = t / 10

To find the spring constant we linearize the equation

        T² = (4π²/K)    m

therefore we see that if we make a graph of T² against the mass, we obtain a line, whose slope is

         m ’= 4π² / k

where m’ is the slope

           k = 4π² / m'

the equation of the line of the attached graph is

       T² = 0.00603 m + 0.0183

therefore the slope

       m ’= 0.00603  s²/g

    we calculate

         k = 4 π² / 0.00603

          k = 6547 g / s²

we reduce the mass to the SI system

         k = 6547 g / s² (1kg / 1000 g)

         k = 6,547 kg / s² =

         k = 6,547 N / m

let's reduce the uniqueness

         [N / m] = [(kg m / s²) m] = [kg / s²]

7 0
3 years ago
An empty plate capacitor is connected between the terminals ofa 9.0 V battery and charged up. The capacitor is then disconnected
777dan777 [17]

Answer:

The new voltage between the parallel plates of the capacitor is 18V, because for a constant electric field, doubling the space between the parallel capacitor plates, will also double the potential difference (voltage) between the plates.

Explanation:

ΔV = E*Δd

Where;

ΔV is the change in potential difference

Δd is the change in the distance between the parallel plates

E is the electric field potential.

Assuming a constant electric field; E = \frac{v}{d} , then; \frac{v_1}{d_1} =\frac{v_2}{d_2}

when the spacing between the capacitor plates is doubled, d₂ = 2d₁

v₂ = (v₁*d₂)/(d₁)

v₂ = (v₁*2d₁)/(d₁)

v₂ = 2v₁

v₂  = 2(9) = 18 V

Therefore, for a constant electric field, doubling the space between the parallel capacitor plates, will also double the potential difference (voltage).

5 0
3 years ago
If the distance between objects is the same for each pair, which of the following have the greatest gravitational force between
tamaranim1 [39]

Answer:

B

Explanation:

3 0
3 years ago
A singer raises his pitch one octave. what quality of the sound wave has changed?
Keith_Richards [23]
I think the amplitude changed 
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sergejj [24]

Answer:

First 8 if wrong then correct me. Second it's direction correct me if wrong.

Explanation:

8 0
2 years ago
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