Calories tell you how much energy is in a food. True or False
2 answers:
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By definition we have to:
The electric current is the flow of electric charge due to the movement (usually of electrons) that a material travels.
Some properties are:
1) Electric conduction: The conductive materials have a large amount of free electrons, therefore, the passage of electricity is possible.
2) The current inside a circuit is directly proportional to the voltage and inversely proportional to the resistance of the circuit. This is what is known as ohm's law:
3) The current can be continuous or alternate.
Alternating current is the electric current in which the magnitude and direction vary cyclically.
The direct current is the flow of electric charges that does not change direction with time.
Answer:
(A) therefore the image is
- 63 cm to the right of the lens
- the image size is -13.22 cm
- it is real
- it is inverted
(B) therefore the image is
- 63 cm to the right of the lens
- the image size is -13.22 cm
- it is real
- it is inverted
Explanation:
height of the insect (h) = 5.25 mm = 0.525 cm
distance of the insect (s) = 25 cm
radius of curvature of the flat left surface (R1) = ∞
radius of curvature of the right surface (R2) = -12.5 cm (because it is a planoconvex lens with the radius in the direction of the incident rays)
index of refraction (n) = 1.7
(A) we can find the location of the image by applying the formula below
where
- s' = distance of the image
- f = focal length
- but we first need to find the focal length before we can apply this formula
f =
f = 17.9 cm
now that we have the focal length we can apply
=\frac{1}{s'}
=\frac{1}{s'}
s' = \frac{447.5}{7.1}[/tex] = 63 cm to the right of the lens
magnification = where y' is the height of the image, therefore
y' = x 0.525 = -13.22 cm
therefore the image is
- 63 cm to the right of the lens
- the image size is -13.22 cm
- it is real
- it is inverted
(B) if the lens is reversed, the radius of curvatures would be interchanged
radius of curvature of the flat left surface (R1) = ∞
radius of curvature of the right surface (R2) = 12.5 cm
we can find the location of the image by applying the formula below
where
- s' = distance of the image
- f = focal length
- but we first need to find the focal length before we can apply this formula
f =
f = 17.9 cm
now that we have the focal length we can apply
=\frac{1}{s'}
=\frac{1}{s'}
s' = \frac{447.5}{7.1}[/tex] = 63 cm to the right of the lens
magnification = where y' is the height of the image, therefore
y' = x 0.525 = -13.22 cm
therefore the image is
- 63 cm to the right of the lens
- the image size is -13.22 cm
- it is real
- it is inverted