Answer:
302.75 Liters
Explanation:
Given:
P = 1 atm
V = ?
n = 13.5 moles
R = 0.0821 atm x L / mole x K
T = 273.15 K
PV = nRT
(1) (V) = (13.5) (0.0821) (273.15)
V = 302.75 Liters
Answer:
464.29mL de solvente y 35.71mL de ácido nítrico concentrado deben agregarse.
Explanation:
El ácido nítrico concentrado viene al 70% v/v por temas de estabilidad. El volumen de ácido nítrico que se debe agregar si se quieren hace 500mL al 5% de HNO3 es:
500mL * (5mL / 100mL) = 25mL de ácido nítrico se deben agregar.
Como el ácido nítrico está al 70%:
25mL ácido nítrico * (100mL / 70mL ácido nítrico) = 35.71mL de ácido nítrico concentrado deben agregarse.
Y el volumen de solvente debe ser:
500mL - 35.71mL = 464.29mL
The answer is 0 if im right
Answer:
potassium hydrogen phthalate KHP MOLAR MASS = 204.233 glmol
to get 1000 ml
Molar concentration = Mass concentration/Molar Mass
mass concentration = molar concentration x molar mass
mass concentration=0.1 M,
molar mass= 204.233 g/mol
so to get 1L
mass conc = 204.233 x 0.1
= 20.4233g for 1L or 1000 ml
to get 6.00 ml
if 20.4233g is for 1000ml
then to 6.00 ml
= 20.4233 x 6 / 1000
= 0.123g for 6.00 ml
according to the equation below
NaOH(aq) + KHC8H4O4(aq) --> KNaC8H4O4(aq) + H2O(l)
number of moles of NaOH is equal to that of KHP
so the same amount will be needed too, which is
= 0.123g
