Answer:
Explanation:
Wave produced in string and waves produced in air are different . The only similarity is that their frequency are equal . Otherwise , no similarity . One is transverse ( on wire ) , the other is longitudinal ( air ) . Their velocities too are different .
velocity = wavelength x frequency
if frequency is constant
wavelength ∝ velocity
wavelength is proportional to velocity . Since their velocities are different , their wavelength too will be different.
Vo = 18 m/s
angle 35 degrees
1) Components of the initial velocity
Vox = Vo*cos(35) = 18*cos(35) m/s = 14.74 m/s
Voy = Vo* sin(35) = 18*sin(35) m/s = 10.32 m/s
2) Equations of postion:
x = Vox*t
y = Voy*t - gt^2 / 2
3) Calculations
A) t = 0.5 s, t = 1.0 st = 1.5 s, t = 2.0 s
x = 14.74 * t
t = 0.5 s => x = 14.74 m/s * 0.5s = 7.37 m
t = 1.0 s => x = 14.74 m/s * 1.0s = 14.74 m
t = 1.5s => x = 22.11 m
t = 2s => x = 29.48 m
B)
y = Voy*t - gt^2 / 2
Voy = 10.32 m/s
g = 10 m/s (approximation)
y = 10.32*t - 5t^2
t = 0.5 s=> y = 3.91m
t = 1 s => y = 5.32m
t = 1.5 s => y = 4.23m
t = 2 s => y = 0.64 m
Answer:
The second law of a vibrating string states that for a transverse vibration in a stretched string, the frequency is directly proportional to the square root of the string's tension, when the vibrating string's mass per unit length and the vibrating length are kept constant
The law can be expressed mathematically as follows;
The second law of the vibrating string can be verified directly, however, the third law of the vibrating string states that frequency is inversely proportional to the square root of the mass per unit length cannot be directly verified due to the lack of continuous variation in both the frequency, 'f', and the mass, 'm', simultaneously
Therefore, the law is verified indirectly, by rearranging the above equation as follows;
From which it can be shown that the following relation holds with the limits of error in the experiment
m₁·l₁² = m₂·l₂² = m₃·l₃² = m₄·l₄² = m₅·l₅²
Explanation:
The correct answer is hang glider.
A hang-glider cannot take off from low ground since it has no power. It needs to be launched from a high location, such a mountain or a hill. The major force acting on a hang-glider is gravity. The weight of the wing and the pilot together is this. The push that keeps the aerofoil flying through the air is produced by the weight. The hang-aerofoil glider's wing's form prevents it from falling to the ground like a stone. It results in lift. An area of low pressure is created by the aerofoil's acceleration of the air passing over the top of the wing. The air moving beneath the wing is compressed as the wing moves forward and downward. After then, the aerofoil is lifted up into the region of low pressure.
The air will gradually drop if it is still. A hang-glider descends at a speed of roughly 3.6 km/h (slow walking), or about 1 meter per second. A hang-glider needs to locate air coming up at the same rate as the glider is going down in order to maintain height. A hang-glider can fly along a cliff without losing height, for instance, if there is a light breeze coming straight from the sea, the air is being forced vertically upward by the cliff at 3.6 km/h, and the glider is flying over a vertical coastal cliff. The glider will begin to gain altitude in a stronger breeze.
Some hang-glider pilots equip their craft with tiny motors and propellers. They become microlights as a result and can now take off and climb from flat ground like a regular aircraft.
To learn more about hang-glider refer the link:
brainly.com/question/1365947
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